제출 #536061

#제출 시각아이디문제언어결과실행 시간메모리
536061browntoadFire (JOI20_ho_t5)C++14
13 / 100
156 ms21896 KiB
#include <bits/stdc++.h> #pragma GCC optimize ("Ofast", "unroll-loops") using namespace std; #define ll long long #define int ll #define FOR(i,a,b) for (int i = (a); i<(b); i++) #define REP(i,n) FOR(i,0,n) #define REP1(i,n) FOR(i,1,n+1) #define RREP(i,n) for (int i=(n)-1; i>=0; i--) #define RREP1(i,n) for (int i=(n); i>=1; i--) #define f first #define s second #define pb push_back #define ALL(x) x.begin(),x.end() #define SZ(x) (int)(x.size()) #define SQ(x) (x)*(x) #define pii pair<int, int> #define pdd pair<double ,double> #define pcc pair<char, char> #define endl '\n' //#define TOAD #ifdef TOAD #define bug(x) cerr<<__LINE__<<": "<<#x<<" is "<<x<<endl #define IOS() #else #define bug(...) #define IOS() ios::sync_with_stdio(0), cin.tie(0), cout.tie(0) #endif const ll inf = 1ll<<60; const int iinf=2147483647; const ll mod = 1e9+7; const ll maxn=2e5+5; const double PI=acos(-1); ll pw(ll x, ll p, ll m=mod){ ll ret=1; while (p>0){ if (p&1){ ret*=x; ret%=m; } x*=x; x%=m; p>>=1; } return ret; } ll inv(ll a, ll m=mod){ return pw(a,m-2); } //======================================================================================= vector<int> seg(4*maxn); vector<int> vc(maxn); void build(int l, int r, int x){ if (l==r){ seg[x]=vc[l]; return; } int mid=(l+r)/2; build(l, mid, x+x); build(mid+1, r, x+x+1); seg[x]=max(seg[x+x], seg[x+x+1]); } int query(int l, int r, int nl, int nr, int x){ if (r<nl||l>nr){ return 0; } if (nl>=l&&nr<=r){ return seg[x]; } int mid=(nl+nr)/2; return max(query(l, r, nl, mid, x+x), query(l, r, mid+1, nr, x+x+1)); } struct typ{ int l, r; int t; }; signed main (){ IOS(); int n, q; cin>>n>>q; REP1(i,n) cin>>vc[i]; vector<typ> vq(q); build(1, n, 1); bool gg=1; REP(i, q){ cin>>vq[i].t>>vq[i].l>>vq[i].r; gg=(gg&(vq[i].l==vq[i].r)); } if (!gg){ vector<int> pf(n+1); REP1(i,n){ int l=max(i-vq[0].t, 1ll); pf[i]=pf[i-1]+query(l, i, 1, n, 1); } REP(i, q){ cout<<pf[vq[i].r]-pf[vq[i].l-1]<<endl; } } else { REP(i, q){ int l=max(vq[i].l-vq[i].t, 1ll); cout<<query(l, vq[i].r, 1, n, 1)<<endl; } } }
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