Submission #535836

#TimeUsernameProblemLanguageResultExecution timeMemory
535836radalFinancial Report (JOI21_financial)C++17
100 / 100
572 ms29808 KiB
#include <bits/stdc++.h> #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native") #pragma GCC optimize("unroll-loops") #define rep(i,l,r) for (int i = l; i < r; i++) #define repr(i,r,l) for (int i = r; i >= l; i--) #define X first #define Y second #define pb push_back #define endl '\n' #define debug(x) cerr << #x << " : " << x << endl; using namespace std; typedef long long ll; typedef long double ld; typedef pair<ll,ll> pll; constexpr ll N = 3e5+20,mod = 1e9+7,inf = 1e9+10,maxm = 1e6; inline int mkay(int a,int b){ if (a+b >= mod) return a+b-mod; if (a+b < 0) return a+b+mod; return a+b; } inline int poww(int a,int k){ if (k < 0) return 0; int z = 1; while (k){ if (k&1) z = 1ll*z*a%mod; a = 1ll*a*a%mod; k >>= 1; } return z; } int a[N],par[N],seg[N*4],dp[N]; int n,d; void upd(int l,int r,int p,int x,int v = 1){ if (r-l == 1){ seg[v] = x; return; } int m = (l+r) >> 1,u = (v << 1); if (p < m) upd(l,m,p,x,u); else upd(m,r,p,x,u|1); seg[v] = max(seg[u],seg[u|1]); } int que(int l,int r,int s,int e,int v = 1){ if (s <= l && r <= e) return seg[v]; if (s >= r || l >= e || s >= e) return 0; int m = (l+r) >> 1,u = (v << 1); return max(que(l,m,s,e,u),que(m,r,s,e,u|1)); } int getpar(int v){ if (v == par[v]) return v; return par[v] = getpar(par[v]); } int main(){ ios :: sync_with_stdio(0); cin.tie(0); cin >> n >> d; vector<pll> ve; rep(i,0,n){ cin >> a[i]; par[i] = i; ve.pb({a[i],-i}); } sort(ve.begin(),ve.end()); set<int> st; int ans = 0; rep(k,0,n){ int i = -ve[k].Y; if (st.empty()){ dp[i] = 1; ans = max(ans,1); st.insert(i); upd(0,n,i,1); continue; } if (i < *(st.begin())){ int j = *(st.begin()); dp[i] = 1; ans = max(ans,1); st.insert(i); if (j-i <= d) par[j] = i; upd(0,n,i,1); continue; } auto it = st.lower_bound(i); it--; int j = (*it); if (i-j <= d) par[i] = getpar(j); dp[i] = 1+que(0,n,par[i],i); ans = max(ans,dp[i]); it++; if (it != st.end()) if((*it)-i <= d) par[(*it)] = i; upd(0,n,i,dp[i]); st.insert(i); } cout << ans; }
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