Submission #534085

#TimeUsernameProblemLanguageResultExecution timeMemory
534085browntoadSelf Study (JOI22_ho_t2)C++14
100 / 100
325 ms5968 KiB
#include <bits/stdc++.h> #pragma GCC optimize ("Ofast", "unroll-loops") using namespace std; #define ll long long #define int ll #define FOR(i,a,b) for (int i = (a); i<(b); i++) #define REP(i,n) FOR(i,0,n) #define REP1(i,n) FOR(i,1,n+1) #define RREP(i,n) for (int i=(n)-1; i>=0; i--) #define f first #define s second #define pb push_back #define ALL(x) x.begin(),x.end() #define SZ(x) (int)(x.size()) #define SQ(x) (x)*(x) #define pii pair<int, int> #define pdd pair<double ,double> #define pcc pair<char, char> #define endl '\n' //#define TOAD #ifdef TOAD #define bug(x) cerr<<__LINE__<<": "<<#x<<" is "<<x<<endl #define IOS() #else #define bug(...) #define IOS() ios::sync_with_stdio(0), cin.tie(0), cout.tie(0) #endif const ll inf = 1ll<<60; const int iinf=2147483647; const ll mod = 1e9+7; const ll maxn=4e5+5; const double PI=acos(-1); std::ostream& operator<<( std::ostream& dest, __int128_t value ) { std::ostream::sentry s( dest ); if ( s ) { __uint128_t tmp = value < 0 ? -value : value; char buffer[ 128 ]; char* d = std::end( buffer ); do { -- d; *d = "0123456789"[ tmp % 10 ]; tmp /= 10; } while ( tmp != 0 ); if ( value < 0 ) { -- d; *d = '-'; } int len = std::end( buffer ) - d; if ( dest.rdbuf()->sputn( d, len ) != len ) { dest.setstate( std::ios_base::badbit ); } } return dest; } ll pw(ll x, ll p, ll m=mod){ ll ret=1; while (p>0){ if (p&1){ ret*=x; ret%=m; } x*=x; x%=m; p>>=1; } return ret; } ll inv(ll a, ll m=mod){ return pw(a,m-2); } //======================================================================================= signed main (){ IOS(); int n,m; cin>>n>>m; vector<int> a(n), b(n); REP(i,n){ cin>>a[i]; } REP(i,n){ cin>>b[i]; } __int128 l=0, r=3; REP(i,23){ r*=10; } //cout<<r<<endl; while(l<=r){ //cout<<l<<' '<<r<<endl; if (l==r){ cout<<l<<endl; break; } __int128 mid=(l+r+1)/2; __int128 debt=0; REP(i,n){ if (max(a[i], b[i])*m>=mid){ __int128 tot=mid/max(a[i], b[i])+(mid%max(a[i], b[i])>0); debt-=m-tot; } else { __int128 mx=mid; mx-=max(a[i], b[i])*m; debt+=mx/b[i]+(mx%b[i]>0); } } if (debt>0){ r=mid-1; } else l=mid; } }
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