Submission #532445

#	Time	Username	Problem	Language	Result	Execution time	Memory
532445		OttoTheDino	Swap (BOI16_swap)	C++17	68 / 100	996 ms	262148 KiB

swap

#include <bits/stdc++.h>
using namespace std;

#define rep(i,s,e)                  for (int i = s; i <= e; ++i)
#define rrep(i,s,e)                 for (int i = s; i >= e; --i)
#define pb                          push_back
#define pf                          push_front
#define fi                          first
#define se                          second
#define all(a)                      a.begin(), a.end()
typedef long long ll;
typedef pair<int, int> ii;
typedef vector<ii> vii;
typedef vector<int> vi;
typedef vector<double> vd;
typedef vector<string> vs;
typedef vector<ll> vll;

const int mx = 2e5;

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);

	int a[2*mx+1];
	map<ii, int> dp;
  
    rep (i,1,2*mx) a[i] = 1e9;

    int n; cin >> n;
    rep (i,1,n) cin >> a[i];

    rrep (i,n,1) {
        vi aff;
        aff.pb(a[i]);
        int p = i/2;
        while (p) {
            if (aff.back()==a[2*p+1]) aff.pb(a[2*p]);
            aff.pb(a[p]);
            p = p/2;
        }
        for (int x : aff) {
            int mi = min(x, min(a[i*2], a[2*i+1]));
            if (x==mi) dp[{i,x}] = 1;
            else if (a[i*2]==mi) dp[{i,x}] = dp[{2*i,x}]+1;
            else {
                if (a[2*i]<x) {
                    if (dp[{2*i, a[2*i]}] <= dp[{2*i+1, a[2*i]}]) dp[{i,x}] = dp[{2*i+1,x}]+1; 
                    else dp[{i,x}] = dp[{2*i,x}]+1;
                }
                else dp[{i,x}] = min(dp[{2*i,x}], dp[{2*i+1,x}])+1;
            }
        }
    }

    rep (i,1,n) {
        int mi = min(a[i], min(a[2*i], a[2*i+1]));
        if (a[2*i+1]==mi) {
            int mi2 = min(a[i], a[2*i]), ma = max(a[i], a[2*i]);
            a[2*i] = mi2;
            a[2*i+1] = ma;
            if (dp[{2*i,mi2}]>dp[{2*i+1,mi2}]) swap (a[2*i], a[2*i+1]);
        }
        else if (a[2*i]==mi) a[2*i] = a[i];
        a[i] = mi;
    }

    rep (i,1,n) cout << a[i] << " \n"[i==n];

    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 11 / 11
• Subtask 3: 27 / 27
• Subtask 4: 20 / 20
• Subtask 5: 0 / 32