# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
5320 | baneling100 | 쉬운 문제 (GA3_easy) | C++98 | 0 ms | 1088 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
int CountPair(int N, int *A)
{
int i, j, cnt=0;
for(i=0 ; i<N-1 ; i++)
for(j=i+1 ; j<N ; j++)
if(A[j]%A[i]==0)
cnt++;
return cnt;
}
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