This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define st first
#define nd second
using lint = int64_t;
constexpr int mod = int(1e9) + 7;
constexpr int inf = 0x3f3f3f3f;
constexpr int ninf = 0xcfcfcfcf;
constexpr lint linf = 0x3f3f3f3f3f3f3f3f;
const long double pi = acosl(-1.0);
// Returns -1 if a < b, 0 if a = b and 1 if a > b.
int cmp_double(double a, double b = 0, double eps = 1e-9) {
return a + eps > b ? b + eps > a ? 0 : 1 : -1;
}
using namespace std;
const int K = 31;
int main() {
cin.tie(nullptr)->sync_with_stdio(false);
int q;
cin>>q;
vector<array<int, 3>>qr(q);
vector<vector<int>>g(1);
int n = 1;
for(int i=0;i<q;i++){
string a;
int x, y;
cin>>a>>x>>y;
int t = (a == "Add") ? 0 : 1;
if(!t) x--;
else x--, y--;
if(!t){
g[x].push_back(n++);
g.push_back({});
}
qr[i] = {t, x, y};
}
vector<int>tin(n), tout(n);
int timer = 0;
auto dfs = [&](auto& self, int u) -> void{
tin[u] = ++timer;
for(int v : g[u]){
self(self, v);
}
tout[u] = timer;
};
dfs(dfs, 0);
vector<int>path(n);
vector<array<int, 2>>trie(1, {-1, -1});
vector<set<int>>s(1);
auto add = [&](int u, int t) ->void{
int cur = 0;
for(int a=K;a>=0;a--){
int b = u>>a&1;
if(trie[cur][b] == -1){
trie[cur][b] = (int)trie.size();
trie.push_back({-1, -1});
s.push_back({});
}
cur = trie[cur][b];
s[cur].insert(t);
}
};
add(0, tin[0]);
int id = 1;
for(auto [t, x, y] : qr){
if(t == 0){
path[id] = path[x] ^ y;
add(path[id], tin[id]);
id++;
}
else{
int w = path[x];
int cur = 0, mask = 0;
for(int a=K;a>=0;a--){
int b = w>>a&1;
if(trie[cur][!b] == -1){
cur = trie[cur][b];
}
else{
int nxt = trie[cur][!b];
auto it = s[nxt].lower_bound(tin[y]);
if(it == s[nxt].end() || (*it) > tout[y]){
cur = trie[cur][b];
}
else{
mask |= (1<<a);
cur = trie[cur][!b];
}
}
}
cout<<mask<<"\n";
}
}
return 0;
}
/*
[ ]Leu o problema certo???
[ ]Ver se precisa de long long
[ ]Viu o limite dos fors (é n? é m?)
[ ]Tamanho do vetor, será que é 2e5 em vez de 1e5??
[ ]Testar sample
[ ]Testar casos de borda
[ ]1LL no 1LL << i
[ ]Testar mod (é 1e9+7, mesmo?, será que o mod não ficou negativo?)
*/
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