Submission #531444

#TimeUsernameProblemLanguageResultExecution timeMemory
531444mat50013Bigger segments (IZhO19_segments)C++11
100 / 100
79 ms16932 KiB
#include <bits/stdc++.h>

using namespace std;
/*
    Am un sir de n numere.
    Trebuie sa-l part in cat mai multe subsecvente astfel inca sumaSubsecv[i] <= sumaSubsecv[i + 1]
    6 2 3 9 13
*/
using ll = long long;
const int NMAX(500005);
int v[NMAX], dp[NMAX];
ll sum[NMAX], bestSol[NMAX];

int main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0), cout.tie(0);

    int n;
    cin >> n;

    for(int i = 1; i <= n; ++i){
        cin >> v[i];
        sum[i] = sum[i - 1] + v[i];
        dp[i] = 1;
        bestSol[i] = sum[i];
    }

    for(int i = 1; i <= n; ++i){
        if(dp[i - 1] > dp[i]){
            dp[i] = dp[i - 1];
            bestSol[i] = bestSol[i - 1] + v[i];
        }
        else if(dp[i - 1] == dp[i])
            bestSol[i] = min(bestSol[i], bestSol[i - 1] + v[i]);
        int nxtPz = lower_bound(sum + i + 1, sum + n + 1, sum[i] + bestSol[i]) - sum;
        if(nxtPz <= n){
            if(dp[i] + 1 > dp[nxtPz]){
                dp[nxtPz] = dp[i] + 1;
                bestSol[nxtPz] = sum[nxtPz] - sum[i];
            }
            else if(dp[i] + 1 == dp[nxtPz])
                bestSol[nxtPz] = min(bestSol[nxtPz], sum[nxtPz] - sum[i]);
        }
    }

    cout << dp[n] << '\n';
    return 0;
}
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