Submission #530801

#	Time	Username	Problem	Language	Result	Execution time	Memory
530801		SavicS	Arranging Shoes (IOI19_shoes)	C++17	10 / 100	6 ms	9704 KiB

shoes

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ld,ld> pdd;
 
#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for (auto& a : x)
 
#define sz(a) (int)(a).size()
#define pb push_back
#define fi first
#define se second
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const int inf = 1e9 + 5;
const int mxN = 200005; 

int n;
int niz[mxN];

vector<int> A[mxN];
vector<int> B[mxN];

ll count_swaps(vector<int> S){
    n = sz(S); ff(i,1,n)niz[i] = S[i - 1];

    ff(i,1,n){
        A[i].clear();
        B[i].clear();
    }

    ff(i,1,n){
        if(niz[i] > 0)A[niz[i]].pb(i);
        if(niz[i] < 0)B[-niz[i]].pb(i);
    }

    ll rez = 0;
    ff(i,1,n){
        sort(all(A[i])); sort(all(B[i]));

        ff(j,0,sz(A[i]) - 1){
            int L = B[i][j];
            int R = A[i][j];

            if(L < R)rez += R - L - 1;
            else rez += L - R;
        }

    }

    return rez;

}

// int main() {
//     cin.tie(0)->sync_with_stdio(0);

//     cin >> n;
//     vector<int> A(n);
//     ff(i,0,n - 1)cin >> A[i];

//     cout << count_swaps(A) << '\n';

//     return 0;
// }
/*
 

 
// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 10 / 10
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 15