Submission #529529

#TimeUsernameProblemLanguageResultExecution timeMemory
529529LucaDantasFortune Telling 2 (JOI14_fortune_telling2)C++17
35 / 100
407 ms262148 KiB
#include <bits/stdc++.h> using namespace std; constexpr int maxn = 2e5+10, inf = 0x3f3f3f3f; struct PersistentSegmentTree { struct Node { Node *l, *r; int val; Node() : l(this), r(this), val(0) {} }; int t = 0; Node *root[maxn]; // we have a root for each version of the seg PersistentSegmentTree() { root[0] = new Node(); } void upd(int pos) { ++t; root[t] = upd(root[t-1], 1, inf, pos); } Node* upd(Node *node, int i, int j, int pos) { // add v to interval l, r /* printf("%d %d\n", i, j); fflush(stdout); */ Node *aq = new Node(); *aq = *node; aq->val++; if(i == j) return aq; int m = (i+j) >> 1; if(pos <= m) aq->l = upd(aq->l, i, m, pos); else aq->r = upd(aq->r, m+1, j, pos); return aq; } int query(Node *node, int i, int j, int l, int r) { // query the interval [l, r] on this version of the seg if(i > r || j < l) return 0; if(i >= l && j <= r) return node->val; int m = (i+j) >> 1; return query(node->l, i, m, l, r) + query(node->r, m+1, j, l, r); } int last(Node *L, Node *R, int i, int j) { if(R->val - L->val == 0) return 0; // trocar pra 0 DEBUG <-----------------------------------------> if(i == j) return i; int m = (i+j) >> 1; int qr = last(L->r, R->r, m+1, j); if(qr != 0) return qr; // trocar pra 0 DEBUG <-----------------------------------------------------> return last(L->l, R->l, i, m); } } segX, segTime; int A[maxn], B[maxn]; pair<int,int> X[maxn]; int main() { int n, k; scanf("%d %d", &n, &k); for(int i = 1; i <= n; i++) scanf("%d %d", A+i, B+i); for(int i = 1; i <= k; i++) { int x; scanf("%d", &x); X[i] = {x, i}; segTime.upd(x); } sort(X+1, X+k+1); for(int i = 1; i <= k; i++) { segX.upd(X[i].second); } long long ans = 0; for(int i = 1; i <= n; i++) { int a = A[i], b = B[i]; if(a > b) swap(a, b); // quero achar o evento com o maior tempo tal que o valor dele está contido em [a, b[ int last = 0; if(a != b) { int itL = (lower_bound(X+1, X+1+k, pair<int,int>(a, 0)) - X) - 1; int itR = (lower_bound(X+1, X+1+k, pair<int,int>(b, 0)) - X) - 1; // printf("%d %d -> %d %d\n", a, b, itL, itR); last = segX.last(segX.root[itL], segX.root[itR], 1, inf); } else last = 0; /* printf("%d %d -> %d %d %d\n", a, b, last, segTime.query(segTime.root[segTime.t], 1, inf, b, inf), segTime.query(segTime.root[segTime.t], 1, inf, b, inf) - segTime.query(segTime.root[last], 1, inf, b, inf)); // >= b */ if(last != 0) ans += (segTime.query(segTime.root[segTime.t], 1, inf, b, inf) - segTime.query(segTime.root[last], 1, inf, b, inf)) % 2 == 0 ? b : a; /* printf("%d\n", segTime.query(segTime.root[segTime.t], 1, inf, b, inf) - segTime.query(segTime.root[last], 1, inf, b, inf) % 2 == 0 ? b : a); */ else ans += segTime.query(segTime.root[segTime.t], 1, inf, b, inf) % 2 == 0 ? A[i] : B[i]; // printf("%d\n", segTime.query(segTime.root[segTime.t], 1, inf, b, inf) % 2 == 0 ? A[i] : B[i]); } printf("%lld\n", ans); }

Compilation message (stderr)

fortune_telling2.cpp: In function 'int main()':
fortune_telling2.cpp:66:17: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   66 |  int n, k; scanf("%d %d", &n, &k);
      |            ~~~~~^~~~~~~~~~~~~~~~~
fortune_telling2.cpp:69:8: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   69 |   scanf("%d %d", A+i, B+i);
      |   ~~~~~^~~~~~~~~~~~~~~~~~~
fortune_telling2.cpp:72:15: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   72 |   int x; scanf("%d", &x); X[i] = {x, i};
      |          ~~~~~^~~~~~~~~~
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...