This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#define X first
#define Y second
using namespace std;
typedef int ll;
typedef pair<ll, ll> pi;
const ll inf = 1e9 + 7, xn = 3e5 + 9;
vector<pi> g[xn], qg[xn];
vector<ll> cnt[xn];
ll ans[xn], f[xn], sz[xn], ti[xn];
bool vis[xn];
void dfs1(ll v, ll p)
{
sz[v] = 1;
for(pi u : g[v]) if(u.Y != p && !vis[u.Y])
{
dfs1(u.Y, v);
sz[v] += sz[u.Y];
}
}
ll dojob(ll v, ll p, ll m)
{
ll mx = 0;
for(pi u : g[v]) if(u.Y != p && !vis[u.Y] && sz[mx] < sz[u.Y]) mx = u.Y;
if(max(m - sz[v], sz[mx]) * 2 <= m) return v;
return dojob(mx, v, m);
}
inline ll get(ll x)
{
ll ret = 0;
while(x > 0) ret += f[x], x -= (x & -x);
return ret;
}
inline void upd(ll x, ll y)
{
while(x < xn) f[x] += y, x += (x & -x);
}
void dfs2(ll v, ll p, ll ls)
{
ti[v] = ls;
upd(ls, 1);
for(pi u : g[v]) if(u.Y != p && !vis[u.Y] && ls <= u.X) dfs2(u.Y, v, u.X);
}
void dfs3(ll v, ll p, ll ls)
{
ti[v] = inf;
upd(ls, -1);
for(pi u : g[v]) if(u.Y != p && !vis[u.Y] && ls <= u.X) dfs3(u.Y, v, u.X);
}
inline void pans(ll x)
{
for(ll i : cnt[x]) ans[i] += get(i);
for(pi i : qg[x]) if(ti[i.Y] <= i.X) ans[i.X] = -1;
}
void dfs4(ll v, ll p, ll ls)
{
pans(v);
for(pi u : g[v]) if(u.Y != p && !vis[u.Y] && u.X <= ls) dfs4(u.Y, v, u.X);
}
void solve(ll v, ll p)
{
dfs1(v, 0);
ll cen = dojob(v, 0, sz[v]);
sort(g[cen].begin(), g[cen].end());
dfs2(cen, 0, 1), pans(cen);
for(pi u : g[cen]) if(u.Y != p && !vis[u.Y])
{
dfs3(u.Y, cen, u.X), upd(ti[cen], -1);
ti[cen] = u.X;
upd(ti[cen], 1), dfs4(u.Y, cen, u.X);
}
vis[cen] = 1;
upd(ti[cen], -1);
ti[cen] = inf;
for(pi u : g[cen]) if(u.Y != p && !vis[u.Y]) solve(u.Y, cen);
}
int main()
{
ios_base::sync_with_stdio(NULL);cin.tie(0);cout.tie(0);
ll n, q;
cin >> n >> q;
q += n, sz[0] = 0;
for(ll i = 1; i < q; i++)
{
ll x, y;
char c;
cin >> c;
if(c == 'S')
{
cin >> x >> y;
g[x].push_back({i, y}), g[y].push_back({i, x});
ans[i] = -3;
}
else if(c == 'C')
{
cin >> x;
cnt[x].push_back(i);
ans[i] = 0;
}
else
{
cin >> x >> y;
qg[y].push_back({i, x});
ans[i] = -2;
}
}
for(ll i = 0; i < n + 2; i++) ti[i] = inf;
solve(1, 0);
for(ll i = 1; i < q; i++)
{
if(ans[i] == -3) continue;
if(ans[i] >= 0) cout << ans[i] << "\n";
else
{
if(ans[i] == -2) cout << "no";
else cout << "yes";
cout << "\n";
}
}
}
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