Submission #528794

#	Time	Username	Problem	Language	Result	Execution time	Memory
528794		NhatMinh0208	DEL13 (info1cup18_del13)	C++14	0 / 100	364 ms	15556 KiB

del13

#ifndef CPL_TEMPLATE
#define CPL_TEMPLATE
/*
	Normie's Template v2.5
	Changes:
    Added warning against using pragmas on USACO.
*/
// Standard library in one include.
#include <bits/stdc++.h>
using namespace std;
 
// ordered_set library.
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
// #define ordered_set(el) tree<el,null_type,less<el>,rb_tree_tag,tree_order_statistics_node_update>
 
// AtCoder library. (Comment out these two lines if you're not submitting in AtCoder.) (Or if you want to use it in other judges, run expander.py first.)
//#include <atcoder/all>
//using namespace atcoder;

//Pragmas (Comment out these three lines if you're submitting in szkopul or USACO.)
// #pragma comment(linker, "/stack:200000000")
// #pragma GCC optimize("Ofast,unroll-loops,tree-vectorize")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")
 
//File I/O.
#define FILE_IN "cseq.inp"
#define FILE_OUT "cseq.out"
#define ofile freopen(FILE_IN,"r",stdin);freopen(FILE_OUT,"w",stdout)
 
//Fast I/O.
#define fio ios::sync_with_stdio(0);cin.tie(0)
#define nfio cin.tie(0)
#define endl "\n"
 
//Order checking.
#define ord(a,b,c) ((a>=b)and(b>=c))
 
//min/max redefines, so i dont have to resolve annoying compile errors.
#define min(a,b) (((a)<(b))?(a):(b))
#define max(a,b) (((a)>(b))?(a):(b))

// Fast min/max assigns to use with AVX.
// Requires g++ 9.2.0.
// template<typename T>
// __attribute__((always_inline)) void chkmin(T& a, const T& b) {
//     a=(a<b)?a:b;
// }

// template<typename T>
// __attribute__((always_inline)) void chkmax(T& a, const T& b) {
//     a=(a>b)?a:b;
// }
 
//Constants.
#define MOD (ll(998244353))
#define MAX 300001
#define mag 320
const long double PI=3.14159265358979;
 
//Pairs and 3-pairs.
#define p1 first
#define p2 second.first
#define p3 second.second
#define fi first
#define se second
#define pii(element_type) pair<element_type,element_type>
#define piii(element_type) pair<element_type,pii(element_type)>
 
//Quick power of 2.
#define pow2(x) (ll(1)<<x)
 
//Short for-loops.
#define ff(i,__,___) for(int i=__;i<=___;i++)
#define rr(i,__,___) for(int i=__;i>=___;i--)
 
//Typedefs.
#define bi BigInt
typedef long long ll;
typedef long double ld;
typedef short sh;

// Binpow and stuff
ll BOW(ll a, ll x, ll p)
{
	if (!x) return 1;
	ll res=BOW(a,x/2,p);
	res*=res;
	res%=p;
	if (x%2) res*=a;
	return res%p;
}
ll INV(ll a, ll p)
{
	return BOW(a,p-2,p);
}
//---------END-------//
#endif
vector<string> vec;
int n,m,i,j,k,t,t1,u,v,a,b;
int dp[100011][3][2];
int arr[100011];
int main()
{
	fio;
	cin>>t;
	for (t1=0;t1<t;t1++) {
		cin>>n>>m;
		for (i=1;i<=n;i++) {
			arr[i]=1;
		}
		arr[n+1]=arr[n+2]=arr[n+3]=-1;
		for (i=1;i<=m;i++) {
			cin>>u;
			arr[u]=0;
		}
		// for (i=1;i<=n;i++) cout<<arr[i]; cout<<endl;
		for (i=0;i<=n+3;i++) for (j=0;j<3;j++) for (k=0;k<2;k++) {
			dp[i][j][k]=0;
		}
		for (i=n;i>=0;i--) for (j=0;j<3;j++) for (k=0;k<2;k++) {
			dp[i][j][k]=0;
			if (i==n) {
				if ((j==0||j==2)&&(k==0)) dp[i][j][k]=1;
			}
			else {
				if (j==0) {
					if (arr[i+1]==0 && dp[i+1][0][k])
					dp[i][j][k]=1;
					if (arr[i+1]==1 && dp[i+1][1][1])
					dp[i][j][k]=5;
					if (arr[i+1]==1 && arr[i+2]==0 && arr[i+3]==1 && dp[i+3][2][0])
					dp[i][j][k]=4;
				}
				if (j==1) {
					if (arr[i+1]==1 && dp[i+1][1][k^1])
					dp[i][j][k]=2;
					if (arr[i+1]==1 && arr[i+2]==0 && arr[i+3]==1 && dp[i+3][2][k])
					dp[i][j][k]=8;
				}
				if (j==2) {
					if (arr[i+1]==1 && dp[i+1][2][k^1])
					dp[i][j][k]=3;
					if (arr[i+1]==1 && dp[i+1][1][0] && k==0)
					dp[i][j][k]=9;
					if (arr[i+1]==1 && arr[i+2]==0 && arr[i+3]==1 && dp[i+3][2][0] && k==0)
					dp[i][j][k]=6;
					if (arr[i+1]==0 && dp[i+1][0][0] && k==0)
					dp[i][j][k]=7;
				}
			}
			cout<<i<<' '<<j<<' '<<k<<dp[i][j][k]<<endl;
		}
		if (dp[0][0][0]) cout<<0<<endl<<endl;
		else cout<<-1<<endl;
	}
}
// a;

• Subtask 1: 0 / 15
• Subtask 2: 0 / 15
• Subtask 3: 0 / 15
• Subtask 4: 0 / 25
• Subtask 5: 0 / 30