Submission #528367

#	Time	Username	Problem	Language	Result	Execution time	Memory
528367		N1NT3NDO	Osumnjičeni (COCI21_osumnjiceni)	C++14	10 / 110	1097 ms	22284 KiB

Main

#include <bits/stdc++.h>
#define ll long long
#define pb push_back
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define sz(x) (int)x.size()
#define fi first
#define sd second
#define all(x) x.begin(), x.end()
//#pragma GCC target ("avx2")
//#pragma GCC optimization ("O3")
//#pragma GCC optimization ("unroll-loops")

using namespace std;
//using namespace __gnu_pbds;

//typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

const int N = (int)2e5 + 5;
int n, l[N], r[N], q, nxt[N], mn[N][22], lg[N];
vector<int> vec;

bool intersect(const pair<int, int> a, const pair<int, int> b)
{
    int L = max(a.fi, b.fi);
    int R = min(a.sd, b.sd);
    return R >= L;
}

int get(int l, int r)
{
    int t = lg[r - l + 1];
    return min(mn[l][t], mn[r - (1 << t) + 1][t]);
}

int main()
{
    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
    cin >> n;
    lg[1] = 0;
    for(int i = 2; i <= n; i++) lg[i] = lg[i / 2] + 1;
    for(int i = 1; i <= n; i++)
    {
        cin >> l[i] >> r[i];
        vec.pb(l[i]);
        vec.pb(r[i]);
    }

    sort(all(vec));
    vec.erase(unique(all(vec)), vec.end());
    for(int i = 1; i <= n; i++)
    {
        l[i] = lower_bound(all(vec), l[i]) - vec.begin(); l[i]++;
        r[i] = lower_bound(all(vec), r[i]) - vec.begin(); r[i]++;
    }

    for(int i = 1; i <= n; i++)
    {
        bool ok = 0;
        for(int j = i + 1; j <= n; j++)
          if (intersect({l[i], r[i]}, {l[j], r[j]}))
            {
                nxt[i] = j;
                ok = 1;
                break;
            }

        if (!ok) nxt[i] = n + 1;
        mn[i][0] = nxt[i];
    }

    for(int i = 1; (1 << i) <= n; i++)
    {
        for(int j = 1; j + (1 << i) - 1 <= n; j++)
          mn[j][i] = min(mn[j][i - 1], mn[j + (1 << (i - 1))][i - 1]);
    }

    cin >> q;
    while(q--)
    {
        int le, ri;
        cin >> le >> ri;
        int i = le, ans = 0;
        while(i <= ri)
        {
            int mn = get(i, nxt[i] - 1);
            mn = min(mn, ri + 1);
            ans++;
            i = mn;
        }

        cout << ans << '\n';
    }
}

• Subtask 1: 0 / 10
• Subtask 2: 10 / 10
• Subtask 3: 0 / 20
• Subtask 4: 0 / 20
• Subtask 5: 0 / 50