This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(), (v).end()
using namespace std;
typedef long long lint;
typedef pair<lint, lint> pi;
const int MAXN = 500005;
struct edge{
int s, e, x;
};
int n, m;
vector<int> gph[MAXN];
int par[20][MAXN], dep[MAXN];
int lca(int x, int y){
if(dep[x] > dep[y]) swap(x, y);
int dx = dep[y] - dep[x];
for(int i = 0; dx; i++){
if(dx & 1) y = par[i][y];
dx >>= 1;
}
for(int i = 19; i >= 0; i--){
if(par[i][x] != par[i][y]){
x = par[i][x];
y = par[i][y];
}
}
if(x != y) return par[0][x];
return x;
}
void dfs(int x, int p = -1){
for(auto &y : gph[x]){
if(y == p) continue;
par[0][y] = x;
dep[y] = dep[x] + 1;
dfs(y, x);
}
}
bool vis[MAXN];
pi dfsl(int x, int p = -1){
pi ret(0, x);
for(auto &y : gph[x]){
if(y == p || vis[y]) continue;
auto ans = dfsl(y, x);
ans.first++;
ret = max(ret, ans);
}
return ret;
}
int main(){
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> m;
vector<edge> qry;
for(int i = 0; i < m; i++){
int s, e, x; cin >> s >> e >> x;
if(x == 1){
gph[s].push_back(e);
gph[e].push_back(s);
}
else{
qry.push_back({s, e, x});
}
}
dfs(0);
for(int i = 1; i < 20; i++){
for(int j = 0; j < n; j++){
par[i][j] = par[i-1][par[i-1][j]];
}
}
int diam = dfsl(dfsl(0).second).first;
int ans = 2 * n - 2 - diam;
for(auto &x : qry){
int l = lca(x.s, x.e);
vector<int> v, w;
for(int i = x.s; i != l; i = par[0][i]) v.push_back(i);
for(int i = x.e; i != l; i = par[0][i]) w.push_back(i);
reverse(all(w));
v.push_back(l);
for(auto &i : w) v.push_back(i);
for(auto &i : v) vis[i] = 1;
vector<int> val;
vector<int> ndiam;
int maxPath = -1e9;
for(auto &i : v){
vis[i] = 0;
val.push_back(dfsl(i).first);
int ndiam = dfsl(dfsl(i).second).first;
maxPath = max(maxPath, ndiam - 3 + sz(v));
vis[i] = 1;
}
for(auto &i : v) vis[i] = 0;
for(int i = 0; i < sz(val); i++){
for(int j = i + 1; j < sz(val); j++){
maxPath = max(maxPath, sz(val) - 1 - j + i + val[i] + val[j]);
}
}
ans = min(ans, 2 * n - 4 + x.x - maxPath);
}
cout << ans << endl;
}
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