Submission #519167

#	Time	Username	Problem	Language	Result	Execution time	Memory
519167		nickmet2004	Longest beautiful sequence (IZhO17_subsequence)	C++11	7 / 100	137 ms	82260 KiB

subsequence

#include<bits/stdc++.h>

using namespace std;
const int N = 1e5 + 5 , M = 10;
int n,a[N] , k[N];
int dp[1<<10][1<<10][M] , p[1<<10][1<<10][M], P[N] , mx , id;
int main (){
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> n;
    for(int i= 0; i< n; ++i) cin >> a[i];
    for(int i = 0; i< n; ++i)cin >> k[i];
    memset(P , -1 , sizeof(P));
    for(int i  =0; i < n; ++i){
        int A = a[i] >> M , B = a[i] & ((1<<M) - 1) , ans = 0;
        for(int l =0; l < (1<<M); ++l){
            int y = k[i] - __builtin_popcount(l & A);
            if(y < 0 || y > 10) continue;
            if(dp[l][B][y] > ans){
                ans = dp[l][B][y];
                P[i] = p[l][B][y];
            }
        }
        ans++;
        if(ans > mx)mx = ans, id = i;
        for(int r= 0; r< (1<<M);++r){
            int y = __builtin_popcount(B & r);
            if(dp[A][r][y] < ans){
                dp[A][r][y] = ans;
                p[A][r][y] = i;
            }
        }
    }
    vector<int> X;
    while(1){
        X.emplace_back(id);
        id = P[id];
        if(id == -1)break;
    }
    reverse(X.begin() , X.end());
    cout << X.size() << endl;
    for(int x : X)cout << x+1 << " ";


}

• Subtask 1: 7 / 7
• Subtask 2: 0 / 16
• Subtask 3: 0 / 17
• Subtask 4: 0 / 60