Submission #519056

#	Time	Username	Problem	Language	Result	Execution time	Memory
519056		Dasha_Gnedko	Bomb (IZhO17_bomb)	C++17	18 / 100	185 ms	30788 KiB

bomb

#include <bits/stdc++.h>

//#include <ext/pb_ds/detail/standard_policies.hpp>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx2")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4")

using namespace std;

//using namespace __gnu_pbds;
//template <typename T> using ordered_set = tree <T, null_type, less < T >, rb_tree_tag, tree_order_statistics_node_update>;

mt19937 gen(time(0));

#define ll long long
#define ld long double
#define pb push_back
#define F first
#define S second
#define TIME clock() * 1.0 / CLOCKS_PER_SEC
#define sz(a) int32_t(a.size())
#define endl '\n'
//#define int long long

const int N = 3100;
const int M = 31;
const int mod = 1e9 + 7;
const ll inf = 1e18 + 7;

int a[N][N];

int32_t main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
//    freopen("input.txt", "r", stdin);
//    freopen("output.txt", "w", stdout);
#endif // LOCAL

    int n, m;
    cin >> n >> m;
    for(int i = 0; i < n; i++)
        for(int j = 0; j < m; j++)
        {
            char c;
            cin >> c;
            a[i][j] = int32_t(c - '0');
        }
    int x = n, y = m, ls = 0;
    for(int i = 0; i < n; i++)
    {
        ls = -1;
        for(int j = 0; j < m; j++)
        {
            if (!a[i][j])
            {
                if (j && a[i][j - 1]) x = min(x, j - ls - 1);
                ls = j;
            }
        }
        if (ls != m - 1) x = min(x, m - ls - 1);
    }
    for(int j = 0; j < m; j++)
    {
        ls = -1;
        for(int i = 0; i < n; i++)
        {
            if (!a[i][j])
            {
                if (i && a[i - 1][j]) y = min(y, i - ls - 1);
                ls = i;
            }
        }
        if (ls != n - 1) y = min(y, n - ls - 1);
    }
    cout << x * y;
}

• Subtask 1: 18 / 100