Submission #515800

#	Time	Username	Problem	Language	Result	Execution time	Memory
515800		Jarif_Rahman	Fire (JOI20_ho_t5)	C++17	8 / 100	1091 ms	51252 KiB

ho_t5

#include <bits/stdc++.h>
#define pb push_back
#define f first
#define sc second
using namespace std;
typedef long long int ll;
typedef string str;

#define debug(s) for(auto x: s) cerr << x << " "; cerr << #s << "\n";

struct segtree{
    struct node{
        ll sm, lazy_sm;
        node(){
            sm = 0, lazy_sm = 0;
        }
        node(ll x){
            sm = x, lazy_sm = 0;
        }
        node operator+(node a){
            node rt;
            rt.sm = sm+a.sm;
            return rt;
        }
        void pushdown_from(node a, int sz){
            sm+=a.lazy_sm*sz;
            lazy_sm+=a.lazy_sm;
        }
    };
    int k;
    vector<node> v;
    segtree(int n){
        k = 1;
        while(k < n) k*=2;
        k*=2;
        v.resize(k, node());
    }
    void add(int l, int r, int nd, int a, int b, ll x){
        if(a > r || b < l) return;
        if(a >= l && b <= r){
            v[nd].sm+=(b-a+1)*x;
            v[nd].lazy_sm+=x;
            return;
        }
        int md = (a+b)/2;
        v[2*nd].pushdown_from(v[nd], md-a+1);
        v[2*nd+1].pushdown_from(v[nd], b-md);
        v[nd].lazy_sm = 0;
        add(l, r, 2*nd, a, md, x);
        add(l, r, 2*nd+1, md+1, b, x);
        v[nd] = v[2*nd]+v[2*nd+1];
    }
    void add(int l, int r, int x){
        add(l, r, 1, 0, k/2-1, x);
    }
    ll sum(int l, int r, int nd, int a, int b){
        if(a > r || b < l) return 0;
        if(a >= l && b <= r) return v[nd].sm;
        int md = (a+b)/2;
        v[2*nd].pushdown_from(v[nd], md-a+1);
        v[2*nd+1].pushdown_from(v[nd], b-md);
        v[nd].lazy_sm = 0;
        ll rt = sum(l, r, 2*nd, a, md) + sum(l, r, 2*nd+1, md+1, b);
        v[nd] = v[2*nd]+v[2*nd+1];
        return rt;
    }
    ll sum(int l, int r){
        return sum(l, r, 1, 0, k/2-1);
    }
};

int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int n, q; cin >> n >> q;
    vector<ll> s(n);
    for(ll &x: s) cin >> x;

    vector<int> prev(n, -1);
    stack<int> st;
    for(int i = n-1; i >= 0; i--){
        while(!st.empty() && s[i] > s[st.top()]) prev[st.top()] = i, st.pop();
        st.push(i);
    }
    while(!st.empty()) st.pop();

    vector<vector<int>> end(n+1);
    vector<vector<pair<int, int>>> chng(n+1);
    for(int i = 0; i < n; i++){
        while(!st.empty() && s[st.top()] <= s[i]){
            int x = st.top();
            st.pop();
            end[i-x-1].pb(x);
            if(prev[x] == -1) continue;
            if(s[prev[x]] <= s[i]) continue;
            chng[i-prev[x]-1].pb({prev[x], i});
        }
        st.push(i);
    }
    while(!st.empty()) end[n-st.top()-1].pb(st.top()), st.pop();

    vector<vector<array<int, 3>>> queries(n);
    for(int i = 0; i < q; i++){
        int t, l, r; cin >> t >> l >> r; t--, l--, r--;
        queries[t].pb({l, r, i});
    }

    vector<ll> ans(q, 0);
    segtree ss(n), s1(n), s2(n);
    for(int i = 0; i < n; i++) ss.add(i, i, s[i]);
    for(int i = 0; i+1 < n; i++) s1.add(i, i, max(0LL, s[i]-s[i+1]));

    for(int t = 1; t <= n; t++){
        for(int in: end[t-1]){
            ll x = s1.sum(in, in);
            if(in != n-1) ss.add(in+1, in+t-1, x);
            s1.add(in, in, -x);
        }
        for(auto [in, nxt]: chng[t-1]){
            ll x = s1.sum(in, in);
            ll y = x-(s[in]-s[nxt]);
            ss.add(in+1, nxt-1, y);
            s1.add(in, in, (s[in]-s[nxt])-x);
        }
        for(auto [l, r, in]: queries[t-1]){
            ans[in]+=ss.sum(l, r);

            int mx, a, b;
            if(t <= r-l+1){
                mx = t;
                a = l, b = r-mx+1;
                a--, b--;
                a = max(a, 0);
            }
            else{
                mx = r-l+1;
                a = r-t+1, b = l;
                a--, b--;
                a = max(a, 0);
            }

            ans[in]+=s1.sum(a, b)*mx;
            for(int i = a-1, c = mx-1; i >= 0 && c > 0; i--, c--) ans[in]+=s1.sum(i, i)*c;
            for(int i = b+1, c = mx-1; i < n && c > 0; i++, c--) ans[in]+=s1.sum(i, i)*c;
        }
    }

    for(ll x: ans) cout << x << "\n";
}

• Subtask 1: 1 / 1
• Subtask 2: 0 / 6
• Subtask 3: 7 / 7
• Subtask 4: 0 / 6
• Subtask 5: 0 / 80