제출 #514822

#제출 시각아이디문제언어결과실행 시간메모리
514822Be_dos별들과 삼각형 (IZhO11_triangle)C++17
100 / 100
588 ms12120 KiB
#include <iostream>
#include <cmath>
#include <cctype>
#include <vector>
#include <algorithm>
#include <set>
#include <map>
#include <deque>
#include <stack>
#include <unordered_set>
#include <sstream>
#include <cstring>
#include <iomanip>
#include <queue>
#include <unordered_map>
#include <random>
#include <cfloat>
#include <chrono>
#include <bitset>
#include <complex>
#include <immintrin.h>
#include <cassert>

int main() {
    int32_t n;
    std::cin >> n;

    std::map<int32_t, int32_t> per_x, per_y;
    std::pair<int32_t, int32_t>* points = new std::pair<int32_t, int32_t>[n];
    for(int32_t i = 0; i < n; i++) {
        int32_t x, y;
        std::cin >> x >> y;

        per_x[x]++;
        per_y[y]++;
        points[i] = {x, y};
    }

    int64_t ans = 0;
    for(int32_t i = 0; i < n; i++)
        ans += (int64_t)(per_x[points[i].first] - 1) * (per_y[points[i].second] - 1);
    std::cout << ans;
    return 0;
}







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