Submission #510723

#TimeUsernameProblemLanguageResultExecution timeMemory
510723KoDKućice (COCI21_kucice)C++17
0 / 110
1 ms204 KiB
#include <bits/stdc++.h> using std::vector; using std::array; using std::pair; using std::tuple; using i64 = std::int64_t; struct Point { int x, y; Point() : x(0), y(0) {} Point(int x, int y) : x(x), y(y) {} friend Point operator-(const Point& p, const Point& q) { return Point(p.x - q.x, p.y - q.y); } friend i64 cross(const Point& p, const Point& q) { return (i64)p.x * q.y - (i64)p.y * q.x; } }; constexpr int MOD = 1000000007; struct Fp { int x; Fp(int x = 0) : x(x) {} Fp& operator+=(const Fp& t) { if ((x += t.x) >= MOD) x -= MOD; return *this; } Fp& operator-=(const Fp& t) { if ((x -= t.x) < MOD) x += MOD; return *this; } Fp& operator*=(const Fp& t) { x = (i64)x * t.x % MOD; return *this; } Fp operator+(const Fp& t) const { return Fp(*this) += t; } Fp operator-(const Fp& t) const { return Fp(*this) -= t; } Fp operator*(const Fp& t) const { return Fp(*this) *= t; } Fp pow(int e) const { Fp ret(1), mul(*this); while (e > 0) { if (e & 1) ret *= mul; mul *= mul; e >>= 1; } return ret; } }; int main() { std::ios_base::sync_with_stdio(false); std::cin.tie(nullptr); int N; std::cin >> N; vector<Point> P(N); for (auto& [x, y] : P) { std::cin >> x >> y; } Fp ans = 0; for (int pivot = 0; pivot < N; ++pivot) { ans += Fp(2).pow(N - 1); vector<Point> above, below; for (int i = 0; i < N; ++i) { if (i != pivot) { const Point p = P[i] - P[pivot]; if (p.y > 0 or (p.x >= 0 and p.y == 0)) { above.push_back(p); } else { below.push_back(p); } } } std::sort(above.begin(), above.end(), [&](const Point& p, const Point& q) { return cross(p, q) > 0; }); std::sort(below.begin(), below.end(), [&](const Point& p, const Point& q) { return cross(p, q) > 0; }); const int n = above.size(), m = below.size(); vector<int> to(n), from(m); for (int i = 0, j = 0; i < n; ++i) { while (j < m and cross(above[i], below[j]) > 0) { j += 1; } to[i] = j; } for (int j = 0, i = 0; j < m; ++j) { while (i < n and cross(below[j], above[i]) > 0) { i += 1; } from[j] = i; } for (int l = 0; l < n; ++l) { for (int r = to[l]; r < m; ++r) { const int all = (n - l - 1) + (m - r - 1) + to[l]; const int between = to[l] + (n - from[r]); ans += Fp(2).pow(all); ans -= Fp(2).pow(all - between); } } } std::cout << ans.x << '\n'; return 0; }
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