Submission #503801

#	Time	Username	Problem	Language	Result	Execution time	Memory
503801		MasterTaster	Fancy Fence (CEOI20_fancyfence)	C++14	12 / 100	1 ms	348 KiB

fancyfence

#include <bits/stdc++.h>

#define pb push_back
#define ll long long
#define pii pair<int, int>
#define xx first
#define yy second
#define MAXN 100010
#define MOD 1000000007

using namespace std;

ll two=500000004; //inv
ll n, dp[MAXN], pos[MAXN], h[MAXN], w[MAXN], pref[MAXN], cnt[MAXN], ress;

ll add(ll x, ll y)
{
    ll ret=x+y;
    if (ret>=MOD) ret-=MOD;
    return ret;
}
ll mul(ll x, ll y)
{
    ll ret=x*y;
    if (ret>=MOD) ret%=MOD;
    return ret;
}
ll sub(ll x, ll y)
{
    ll ret=x-y;
    if (ret<0) ret+=MOD;
    return ret;
}
ll sum(ll x, ll y)
{
    ll ret=mul(mul(y, y+1), two);
    ret-=mul(mul(x-1, x), two);
    if (ret<0) ret+=MOD;
    return ret;
}

int main(){
    ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);

    cin>>n;
    for (int i=1; i<=n; i++) cin>>h[i];
    for (int i=1; i<=n; i++) cin>>w[i];


    stack<pii> st;
    st.push({-1, 0});
    for (int i=1; i<=n; i++)
    {
        while (st.top().xx>h[i]) st.pop();
        pos[i]=st.top().yy;
        st.push({h[i], i});
    }

    pref[0]=0;
    for (int i=1; i<=n; i++) pref[i]=add(pref[i-1], w[i]);


    ll x, y;
    cnt[1]=sum(1, h[1]);
    for (int i=2; i<=n; i++)
    {
        int ind=pos[i];
        cnt[i]=cnt[ind];

        x=pref[i]-pref[ind];
        y=sum(1, h[i]);
        ll pom=mul(x, y);

        cnt[i]=add(cnt[i], pom);
    }

    dp[1]=mul(sum(1, w[1]), sum(1, h[1]));
    for (int i=2; i<=n; i++)
    {
        int ind=pos[i];
        dp[i]=mul(cnt[ind], w[i]);

        x=mul(pref[i-1]-pref[ind], w[i]);
        y=sum(1, h[i]);
        dp[i]=add(dp[i], mul(x, y));

        x=sum(1, w[i]);
        y=sum(1, h[i]);
        dp[i]=add(dp[i], mul(x, y));
    }

    for (int i=1; i<=n; i++) { ress=add(dp[i], ress); /*cout<<cnt[i]<<" "<<dp[i]<<endl;*/ }
    //cout<<endl;

    cout<<ress;
}
/*

3
1 2 1
1 2 3

*/

• Subtask 1: 0 / 0
• Subtask 2: 12 / 12
• Subtask 3: 0 / 13
• Subtask 4: 0 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 18
• Subtask 7: 0 / 27