This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "bits/stdc++.h"
using namespace std;
#define ar array
#define int long long
const int N = 5e5 + 5;
struct ST{
int tree[N * 4], add[N * 4], p[N * 4];
void sett(int i, int v, int lx = 0, int rx = N, int x = 1){
if(lx == rx) { add[x] = v; return; }
int m = (lx + rx) >> 1;
if(i <= m) sett(i, v, lx, m, x<<1);
else sett(i, v, m+1, rx, x<<1|1);
add[x] = max(add[x<<1], add[x<<1|1]);
}
void push(int x, int lx, int rx){
if(lx == rx || !p[x]) return;
tree[x<<1] = max(tree[x<<1], p[x] + add[x<<1]);
tree[x<<1|1] = max(tree[x<<1|1], p[x] + add[x<<1|1]);
p[x<<1] = max(p[x<<1], p[x]), p[x<<1|1] = max(p[x<<1|1], p[x]);
p[x] = 0;
}
void umax(int l, int r, int v, int lx = 0, int rx = N, int x = 1){
if(lx > r || rx < l) return;
if(lx >= l && rx <= r){
tree[x] = max(tree[x], v + add[x]);
p[x] = max(p[x], v); return;
} push(x, lx, rx); int m = (lx + rx) >> 1;
umax(l, r, v, lx, m, x<<1), umax(l, r, v, m+1, rx, x<<1|1);
tree[x] = max(tree[x<<1], tree[x<<1|1]);
}
int get(int l, int r, int lx = 0, int rx = N, int x = 1){
if(lx > r || rx < l) return 0;
if(lx >= l && rx <= r) return tree[x];
push(x, lx, rx);
int m = (lx + rx) >> 1;
return max(get(l, r, lx, m, x<<1), get(l, r, m+1, rx, x<<1|1));
}
}tree;
signed main(){
ios::sync_with_stdio(0); cin.tie(0);
int n; cin>>n;
vector<int> a(n);
for(int i=0;i<n;i++) cin>>a[i];
vector<vector<ar<int, 2>>> qq(n);
int q; cin>>q;
for(int i=0;i<q;i++){
int l, r; cin>>l>>r; l--, r--;
qq[l].push_back({r, i});
}
for(int i=0;i<n;i++) tree.sett(i, a[i]);
vector<int> ss;
vector<vector<int>> pp(n);
for(int i=0;i<n;i++){
while(!ss.empty() && a[ss.back()] < a[i]) ss.pop_back();
if(!ss.empty()) pp[ss.back()].push_back(i);
ss.push_back(i);
} ss.clear();
for(int i=n-1;~i;i--){
while(!ss.empty() && a[ss.back()] < a[i]) ss.pop_back();
if(!ss.empty()) pp[i].push_back(ss.back());
ss.push_back(i);
}
vector<int> res(q);
for(int i=n-1;~i;i--){
for(auto j : pp[i]){
if(j + j - i < n) tree.umax(j + j - i, n - 1, a[i] + a[j]);
}
for(auto x : qq[i]){
res[x[1]] = tree.get(i, x[0]);
}
}
for(int i=0;i<q;i++) cout<<res[i]<<"\n";
}
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