제출 #502636

#제출 시각아이디문제언어결과실행 시간메모리
502636stanislavpolynIntergalactic ship (IZhO19_xorsum)C++17
17 / 100
2080 ms2252 KiB
#include <bits/stdc++.h>

#define fr(i, a, b) for(int i = (a); i <= (b); ++i)
#define rf(i, a, b) for(int i = (a); i >= (b); --i)
#define fe(x, y) for(auto& x : y)

#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define mt make_tuple

#define all(x) (x).begin(), (x).end()
#define sz(x) (int)(x).size()
#define pw(x) (1LL << (x))

using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<typename T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define fbo find_by_order
#define ook order_of_key

template<typename T>
bool umn(T& a, T b) { return (a > b ? (a = b, 1) : 0); }
template<typename T>
bool umx(T& a, T b) { return (a < b ? (a = b, 1) : 0); }

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template<typename T>
using ve = vector<T>;

const int N = 1e3 + 5;
const int MOD = 1e9 + 7;

int add(int a, int b) {
    a += b;
    if(a >= MOD) {
        return a - MOD;
    }
    return a;
}

int sub(int a, int b) {
    a -= b;
    if(a < 0) {
        return a + MOD;
    }
    return a;
}

int mult(int a, int b) {
    return 1LL * a * b % MOD;
}

int n, q;
int a[N], was[N];
int pref[N];
ve<array<int, 3>> Q;

int main() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
    ios::sync_with_stdio(0);
    cin.tie(0);
#else
//    freopen("input.txt", "r", stdin);
//    freopen("output.txt", "w", stdout);
    ios::sync_with_stdio(0);
    cin.tie(0);
#endif

    cin >> n;

    fr(i, 1, n) {
        cin >> a[i];
        was[i] = a[i];
    }

    cin >> q;
    Q.resize(q);
    int res = 0;
    fr(i, 0, q - 1) {
        cin >> Q[i][0] >> Q[i][1] >> Q[i][2];
    }

    fr(mask, 0, pw(q) - 1) {
        fr(i, 1, n) a[i] = was[i];
        fr(i, 0, q - 1) {
            if(mask & pw(i)) {
                fr(j, Q[i][0], Q[i][1]) a[j] ^= Q[i][2];
            }
        }
        int sum1 = 0;
        int sum2 = 0;
        fr(i, 1, n) {
            pref[i] = add(a[i], pref[i - 1]);

            res = add(res, mult(i, mult(pref[i], pref[i])));
            res = sub(res, mult(sum1, mult(2, pref[i])));
            res = add(res, sum2);

            sum1 = add(sum1, pref[i]);
            sum2 = add(sum2, mult(pref[i], pref[i]));
        }
    }

    cout << res << "\n";

    return 0;
}
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