Submission #500771

#TimeUsernameProblemLanguageResultExecution timeMemory
500771MazaalaiHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++17
64 / 100
3033 ms262144 KiB
#include <bits/stdc++.h> #define pb push_back #define ff first #define ss second #define LINE "----------------------\n" #define ALL(x) x.begin(),x.end() using namespace std; using ll = long long; using PII = pair <int, int>; using VI = vector <int>; using VVI = vector <VI>; using VPI = vector <PII>; const int N = 1e6 + 5; const int M = 4 * N; int nums[N]; struct Node { int maxInv; vector <int> vals; Node() { maxInv = -1; } void init(int l, int r) { int curMax = nums[l]; vals.pb(nums[l]); for (int i = l+1; i <= r; i++) { vals.pb(nums[i]); if (nums[i] >= curMax) curMax = nums[i]; else maxInv = max(maxInv, curMax+nums[i]); } sort(ALL(vals)); } int findSmaller(int x) { int id = lower_bound(ALL(vals), x) - vals.begin(); return (id ? vals[id-1] : -1); } }; Node node[M]; int n, m; void build(int l, int r, int head) { node[head].init(l, r); if (l == r) return; int mid = (l+r)>>1; build(l, mid, head*2+1); build(mid+1, r, head*2+2); } PII zero = {-1, -1}; int maxQuery(int l, int r, int L, int R, int mx, int head) { // returns MaxInv, ans maxEl if (l > R || L > r) return -1; if (L <= l && r <= R) return node[head].findSmaller(mx); int mid = (l+r)>>1; return max( maxQuery(l, mid, L, R, mx, head*2+1), maxQuery(mid+1, r, L, R, mx, head*2+2) ); } PII query(int l, int r, int L, int R, int head) { // returns MaxInv, ans maxEl if (l > R || L > r) return zero; if (L <= l && r <= R) return {node[head].maxInv, node[head].vals.back()}; int mid = (l+r)>>1; PII lhs = query(l, mid, L, R, head*2+1); PII rhs = query(mid+1, r, L, R, head*2+2); int maxAns = max(lhs.ff, rhs.ff); if (lhs.ss != -1) { int mx = maxQuery(mid+1, r, L, R, lhs.ss, head*2+2); // int mx = node[head*2+2].findSmaller(lhs.ss); if (mx != -1) maxAns = max(maxAns, lhs.ss + mx); } return {maxAns, max(lhs.ss, rhs.ss)}; } signed main() { // freopen("in.txt", "r", stdin); // freopen("out.txt", "w", stdout); cin >> n >> m; for (int i = 1; i <= n; i++) cin >> nums[i]; build(1, n, 0); for (int i = 0; i < m; i++) { int l, r, k; cin >> l >> r >> k; // cout << LINE; int cur = query(1, n, l, r, 0).ff; // cout << l << ' ' << r << ' ' << cur << '\n'; cout << (cur > k ? 0 : 1) << "\n"; } }
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