Submission #499284

#	Time	Username	Problem	Language	Result	Execution time	Memory
499284		avaneeshk098	Lun (COCI19_lun)	C++17	5 / 50	1 ms	320 KiB

lun

#include <bits/stdc++.h>
#pragma GCC optimize "trapv"

#define ff              first
#define int 			long long int
#define ss              second
#define pb              push_back
#define mp              make_pair
#define mt              make_tuple
#define pii             pair<int,int>
#define vi              vector<int>
#define mii             map<int,int>
#define pqb             priority_queue<int>
#define max_size        100000000
#define pqs             priority_queue<int,vi,greater<int> >
#define setbits(x)      __builtin_popcountll(x)
#define mod             (int)1e9+7
#define w(t)			int t; cin >> t; while(t--)
#define inf             1e18
//#define ps(x,y)         fixed<<setprecision(y)<<x
#define mk(arr,n,type)  type *arr=new type[n];
#define range(a,b)      substr(a,b-a+1)
#define mina(a,b,c)		min(a, min(b, c))
#define maxa(a,b,c)		max(a, max(b, c))
#define sz(a)			(int)a.size()	
#define endl 			'\n'
#define trace(x)        cerr<<#x<<": "<<x<<" "<<endl;
#define FIO             ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define FOR(x,y)		for(int i = x; i < y; i++)
#define rrep(a,b,x,y)	for(int x = 0; x < a; x++) for(int y = 0; y < b; y++)
#define rrep1(a,b,x,y)	for(int x = 1; x <= a; x++) for(int y = 0; y <= b; y++)
#define rrepo(a,b,x,y)	for(int x = 0; x < a; x++){ for(int y = 0; y < b; y++)
#define rrepo1(a,b,x,y)	for(int x = 1; x <= a; x++){ for(int y = 0; y <= b; y++)

	
using namespace std;

bool sortbysecond(const pair<int,int> &a, const pair<int,int> &b){ return (a.first > b.first); } 

int64_t ceil_div(int64_t a, int64_t b) {if(a%b != 0){ return ((a/b)+1);} else{ return (a/b);}}

double max(double a, double b){ if(a >= b){ return a; } else{ return b; } }

double min(double a, double b){if(a <= b){return a;} else{return b;	}}

bool modd(double a, double b){if(floor(a/b) == ceil(a/b)){return true;} return false;}

bool stringsort(const string &a, const string &b){return a.length() > b.length();}

bool specsort(const pair<long double,int> &a, const pair<long double,int> &b){ 
	return a.first - a.second > b.first - b.second;  
}

struct ufds{
	vi link, siz;
	int cmp;
	ufds(int n) : link(n), siz(n,1) { iota(link.begin(), link.end(), 0); cmp = n;}
	int find(int x){
		if(x == link[x]) return x;
		return link[x] = find(link[x]);
	}
	
	bool same(int x, int y){
		return find(x) == find(y);
	}
	
	bool unite(int x, int y){
		x = find(x);
		y = find(y);
		if(x == y) return false;
		if(x < y) swap(x,y);
		siz[x] += siz[y];
		link[y] = x;
		cmp--;
		return true;
	}
	
	int components(){
		return cmp;
	}
	
	bool size(int x){ 
		return siz[find(x)];
	}
	
	void print(){
		for(auto i : siz) cout << i << " ";
		cout << endl;
	}
};

struct segtree{
	vi a;
	vector<int> seg;
	segtree(int n, vi &b) : seg(4*n) { a = b; }
	
	void build(int l, int r, int pos){
		if(l == r){ // if l == r it means it is a laef node so only 1 minimum
			seg[pos] = a[l-1];
			return;
		}
		int mid = (l+r)/2;
		build(l,mid, pos*2); // filling left tree for minimum
		build(mid+1, r, pos*2+1); // filling right tree for minimum
		seg[pos] = max(seg[pos*2], seg[pos*2+1]);
	}
	
	int query(int l, int r, int ql, int qr, int pos){
		if(l > qr || r < ql) return 0;
		if(l >= ql && r <= qr) return seg[pos];
		int mid = (l+r)/2;
		int q1 = query(l, mid, ql, qr, pos*2);
		int q2 = query(mid+1, r, ql, qr, pos*2 + 1);
		return max(q1,q2);
	}
	
	void print(){
		for(auto i : seg) cout << i << " ";
		cout << endl;
	}
};

void solve(){	
	int n;
	cin >> n;
	string s;
	cin >> s;
	int c = 0;
	int l = s[n-1]-'0';
	if(s[n-1] == 'x') l = 10;
	reverse(s.begin(), s.end());
	for(int i = 1; i < n; i+=2){
		if(s[i] == 'x') continue;
		c+=(s[i] - '0')*2;
	}
	for(int i = 0; i < n; i+=2){
		if(s[i] == 'x') continue;
		c+=(s[i] - '0');
	}
	for(int i = 0; i  <= 9; i++){
		if(l == 10){
			cout << ((c+i)*9)%10 << endl;
			return;
		}
		if(l == ((c+i)*9)%10){
			cout << i << endl;
			return;
		}
	}
}

int32_t main(){
	FIO;
	//w(t){solve();}
	solve();
    return 0; 
}

• Subtask 1: 5 / 50