Submission #498985

#	Time	Username	Problem	Language	Result	Execution time	Memory
498985		inksamurai	Klasika (COCI20_klasika)	C++17	0 / 110	2174 ms	129820 KiB

klasika

#include <bits/stdc++.h>
#define fi first
#define se second
#define pb push_back
#define sz(a) (int)a.size()
#define all(a) a.begin(),a.end()
#define rep(i,n) for(int i=0;i<n;i++)
#define crep(i,x,n) for(int i=x;i<n;i++)
#define drep(i,n) for(int i=n-1;i>=0;i--)
#define vec(...) vector<__VA_ARGS__>
#define _3qplfh5 ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0)
using namespace std;
typedef long long ll;
typedef long double ld;
using tupiii=tuple<int,int,int>;
using pii=pair<int,int>;
using vi=vector<int>;
using vll=vector<long long>;

int main(){
_3qplfh5;
	int q;
	cin>>q;
	vec(tupiii) qry;
	int n=1;
	rep(_,q){
		string s;
		cin>>s;
		int t=0;
		if(s=="Add"){
			t=1;
			n++;
		}
		int _a,_b;
		cin>>_a>>_b;
		qry.pb({t,_a,_b});
	}
	vec(vec(pii)) adj(n);
	int now=1;
	for(auto [t,_a,_b] : qry){
		if(t==1){
			adj[_a-1].pb({now,_b});
			adj[now].pb({_a-1,_b});
			now++;
		}
	}
	//rabbit tour
	vi tour;
	vi tin(n,0),tout(n,0);
	vi psum(n,0);
	int tm=0;
	auto dfs=[&](auto self,int v,int par)->void{
		tin[v]=tm++;
		tour.pb(v);
		for(auto edge : adj[v]){
			int u=edge.fi;
			if(u!=par){
				psum[u]=psum[v]^edge.se;
				// cout<<edge.se<<"\n";
				self(self,u,v);
			}
		}
		tout[v]=tm++;
		tour.pb(v);
	};
	dfs(dfs,0,-1);
	vec(std::map<ll,set<int>>) rbts(32);
	now=1;
	for(auto [t,_a,_b] : qry){
		if(t==0){
			_a--,_b--;
			int k=psum[_a];
			int need=0;
			drep(j,31){
				if(!(k&(1<<j))){
					need|=(1<<j);
				}
				bool pokita=0;
				if(rbts[j].find(need)!=rbts[j].end()){
					auto it=rbts[j][need].lower_bound(tin[_b]);
					if(it!=rbts[j][need].end() and *it<tout[_b]){
						pokita=1;
					}
				}
				if(not pokita){
					need^=(1<<j);
				}
			}
			cout<<(need^k)<<"\n";
		}else{
			int v=now;
			int wata=0;
			drep(j,31){
				if(psum[v]&(1<<j)) wata|=(1<<j);
				rbts[j][wata].insert(tin[v]);
			}
			// cout<<psum[v]<<"\n";
			now++;
		}
	}
//	
	return 0;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 22
• Subtask 3: 0 / 33
• Subtask 4: 0 / 44