Submission #498984

#	Time	Username	Problem	Language	Result	Execution time	Memory
498984		Victor	Selotejp (COCI20_selotejp)	C++17	110 / 110	186 ms	81728 KiB

Main

// #pragma GCC target ("avx,avx2,fma")
// #pragma GCC optimize ("Ofast,inline") // O1 - O2 - O3 - Os - Ofast
// #pragma GCC optimize ("unroll-loops")
#include <bits/stdc++.h>

using namespace std;

#define rep(i, a, b) for (int i = (a); i < (b); ++i)
#define per(i, a, b) for (int i = (b - 1); i >= (a); --i)
#define trav(a, x) for (auto &a : x)

#define all(x) x.begin(), x.end()
#define sz(x) x.size()
#define pb push_back
#define debug(x) cout << #x << " = " << x << endl

#define umap unordered_map
#define uset unordered_set

typedef pair<int, int> ii;
typedef pair<int, ii> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<vi> vvi;

typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<pll> vpll;

const int INF = 1'000'000'007;

int rows, cols, memo[1001][1 << 10][10][2];
string grid[1001];

int turn_off(int mask, int col) { return mask & ((1 << cols) - 1 - (1 << col)); }

int dp(int row, int mask, int col, int prev) {
    if (row == rows) return 0;

    int &ans = memo[row][mask][col][prev];
    if (ans != -1) return ans;

    int ncol = col + 1, nrow = row;
    if (ncol == cols) {
        ncol = 0;
        ++nrow;
    }

    if (grid[row][col] == '.') {
        ans = dp(nrow, turn_off(mask, col), ncol, 0);

    } else {
        int add = !prev;
        ans = dp(nrow, turn_off(mask, col), ncol, 1 && ncol) + add;

        add = (mask & (1 << col)) == 0;
        ans = min(ans, dp(nrow, mask | (1 << col), ncol, 0) + add);
        //cout << "row = " << row << " mask = " << mask << " col = " << col << " prev = " << prev<<" ans = "<<ans << endl;
    }

    return ans;
}

void print_dp(int row, int mask,int col,int prev) {
    if(row==rows)return;
}

int main() {
    cin.tie(0)->sync_with_stdio(0);
    cin.exceptions(cin.failbit);

    memset(memo, -1, sizeof(memo));
    cin >> rows >> cols;
    rep(i, 0, rows) cin >> grid[i];
    cout << dp(0, 0, 0, 0) << endl;
    return 0;
}

• Subtask 1: 35 / 35
• Subtask 2: 35 / 35
• Subtask 3: 40 / 40