This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
#define all(v) v.begin(),v.end()
#define pb push_back
#define sz size()
#define ft first
#define sd second
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef unsigned long long ull;
const int N = 1e6 + 5;
const ll M = 1e8;
const ll inf = 1e18;
const ll mod = 1e9;
const double Pi = acos(-1);
ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); }
bool odd(ll n) { return (n % 2 == 1); }
bool even(ll n) { return (n % 2 == 0); }
ll n, m, a[N], t[N * 4], ans[N];
vector <pair<pll, ll>> q[N];
vector <ll> v;
void upd(ll pos, ll val, ll v = 1, ll tl = 1, ll tr = n) {
if (tl == tr) {
t[v] = val;
return;
}
ll tm = (tl + tr) / 2;
if (pos <= tm) upd(pos, val, v + v, tl, tm);
else upd(pos, val, v + v + 1, tm + 1, tr);
t[v] = max(t[v + v], t[v + v + 1]);
}
ll get(ll l, ll r, ll v = 1, ll tl = 1, ll tr = n) {
if (r < tl || tr < l) return 0;
if (l <= tl && tr <= r) return t[v];
ll tm = (tl + tr) / 2;
return max(get(l, r, v + v, tl, tm), get(l, r, v + v + 1, tm + 1, tr));
}
const void solve(/*Armashka*/) {
cin >> n >> m;
for (int i = 1; i <= n; ++ i) cin >> a[i];
for (int i = 1; i <= m; ++ i) {
ll l, r, k;
cin >> l >> r >> k;
q[r].pb({{l, k}, i});
}
v.pb(0);
for (int i = 1; i <= n; ++ i) {
while (v.back() > 0 && a[v.back()] <= a[i]) v.pop_back();
if (v.back() > 0) upd(v.back(), a[v.back()] + a[i]);
v.pb(i);
while (q[i].sz) {
ll l = q[i].back().ft.ft, r = i, k = q[i].back().ft.sd, id = q[i].back().sd;
q[i].pop_back();
if (get(l, r) <= k) ans[id] = 1;
}
}
for (int i = 1; i <= m; ++ i) cout << ans[i] << "\n";
}
signed main() {
fast;
//freopen("divide.in", "r", stdin);
//freopen("divide.out", "w", stdout);
int tt = 1;
//cin >> tt;
while (tt --) {
solve();
}
}
/*
5 4 4
1 2
3 1
3 4
5 3
4 5 2 3
2 1 3 1
1 3 5
2 3 4 5
2 1 3 1
*/
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