Submission #496342

#	Time	Username	Problem	Language	Result	Execution time	Memory
496342		armashka	Nice sequence (IZhO18_sequence)	C++17	34 / 100	990 ms	262148 KiB

sequence

#include <bits/stdc++.h>
 
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
 
#define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr);
#define all(v) v.begin(),v.end()
#define pb push_back
#define sz size()
#define ft first
#define sd second
 
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef unsigned long long ull;
 
const int N = 5e5 + 5;
const ll M = 1e8;
const ll inf = 1e9;
const ll mod = 1e9;
const double Pi = acos(-1); 
 
ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;}
ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); }
bool odd(ll n) { return (n % 2 == 1); }
bool even(ll n) { return (n % 2 == 0); }            
 
int n, m, used[N], pr[N], len;
vector <int> g[N], order;
bool ok;
 
void qfs(int v, int mx) {
    used[v] = 1;
    for (auto to : g[v]) { 
        if (to > mx) continue;
        qfs(to, mx);
    }
    order.pb(v);
}
 
const void solve(/*Armashka*/) {
    cin >> n >> m;
    ll len = n + m - 1 - __gcd(n, m);
	for (int i = 0; i <= len; ++ i) used[i] = 0;
	for (int i = 0; i <= len; ++ i) {
        if (i >= n) g[i - n].pb(i);
        if (i >= m) g[i].pb(i - m);
    }
    for (int i = 0; i <= len; ++ i) {
       if (!used[i]) qfs(i, len);
    }
    reverse(all(order));
    for (int i = 0; i <= len; ++ i) {
        pr[order[i]] = i;
    } 
    cout << len << "\n";
    for (int i = 1; i <= len; ++ i) {
        cout << -(pr[i] - pr[i - 1]) << " ";
    }
    cout << "\n";
    for (int i = 0; i <= 4e5; ++ i) pr[i] = 0, g[i].clear();
    order.clear();
}
 
signed main() {
    fast;
    //freopen("divide.in", "r", stdin);
    //freopen("divide.out", "w", stdout);
    int tt = 1;
    cin >> tt;
    while (tt --) {
        solve();
    }
}
 
/*
5 4 4
1 2
3 1
3 4
5 3
4 5 2 3
2 1 3 1
1 3 5
2 3 4 5
2 1 3 1
*/

• Subtask 1: 6 / 6
• Subtask 2: 0 / 9
• Subtask 3: 14 / 14
• Subtask 4: 0 / 15
• Subtask 5: 14 / 14
• Subtask 6: 0 / 18
• Subtask 7: 0 / 24