Submission #496020

#TimeUsernameProblemLanguageResultExecution timeMemory
496020armashkaNice sequence (IZhO18_sequence)C++17
34 / 100
1016 ms262148 KiB
#include <bits/stdc++.h> //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr); #define all(v) v.begin(),v.end() #define pb push_back #define sz size() #define ft first #define sd second using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef unsigned long long ull; const int N = 5e5 + 5; const ll M = 1e8; const ll inf = 1e9; const ll mod = 1e9; const double Pi = acos(-1); ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;} ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;} ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); } bool odd(ll n) { return (n % 2 == 1); } bool even(ll n) { return (n % 2 == 0); } int n, m, used[N], pr[N], len; vector <int> g[N], order; bool ok; void dfs(int v, int mx) { used[v] = 1; for (auto to : g[v]) { if (to > mx) continue; if (used[to] == 1) { ok = 0; } if (!used[to]) dfs(to, mx); } used[v] = 2; } bool check(int x) { ok = 1; for (int i = 0; i <= x; ++ i) used[i] = 0; for (int i = 0; i <= x; ++ i) { if (used[i] == 0) { dfs(i, x); } } return ok; } void qfs(int v, int mx) { used[v] = 1; for (auto to : g[v]) { if (to > mx) continue; qfs(to, mx); } order.pb(v); } const void solve(/*Armashka*/) { cin >> n >> m; if (n == 1 && m == 1) { cout << "0\n"; return; } for (int i = 0; i <= 4e5; ++ i) { if (i >= n) g[i - n].pb(i); if (i >= m) g[i].pb(i - m); } int l = 1, r = n + m; while (l <= r) { int mid = (l + r) / 2; if (check(mid)) l = mid + 1, len = mid; else r = mid - 1; } for (int i = 0; i <= len; ++ i) used[i] = 0; for (int i = 0; i <= len; ++ i) { if (!used[i]) qfs(i, len); } reverse(all(order)); for (int i = 0; i <= len; ++ i) { pr[order[i]] = i; } cout << len << "\n"; for (int i = 1; i <= len; ++ i) { cout << -(pr[i] - pr[i - 1]) << " "; } cout << "\n"; for (int i = 0; i <= 4e5; ++ i) pr[i] = 0, g[i].clear(); order.clear(); } signed main() { fast; //freopen("divide.in", "r", stdin); //freopen("divide.out", "w", stdout); int tt = 1; cin >> tt; while (tt --) { solve(); } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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