Submission #495761

#TimeUsernameProblemLanguageResultExecution timeMemory
495761armashkaSegments (IZhO18_segments)C++17
0 / 100
5094 ms3840 KiB
#include <bits/stdc++.h> //#pragma comment(linker, "/stack:200000000") //#pragma GCC optimize("Ofast") //#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #define fast ios_base::sync_with_stdio(false);cin.tie(nullptr);cout.tie(nullptr); #define all(v) v.begin(),v.end() #define pb push_back #define sz size() #define ft first #define sd second using namespace std; typedef long long ll; typedef pair<ll, ll> pll; typedef unsigned long long ull; const int N = 3e5 + 5; const ll M = 1e8; const ll inf = 1e3; const ll mod = 1e9; const double Pi = acos(-1); ll binpow(ll x, ll ti) { ll res = 1;while (ti){if(ti & 1)res *= x;x *= x;ti >>= 1; x %= mod; res %= mod;} return res;} ll binmul(ll x, ll ti) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= mod; res %= mod;} return res;} ll nok(ll a, ll b) { return (a*b)/__gcd(abs(a),abs(b)) * (a*b > 0 ? 1 : -1); } bool odd(ll n) { return (n % 2 == 1); } bool even(ll n) { return (n % 2 == 0); } int n, t, last, cur; multiset<pair<int,pair<int, int>>> st; pair<int,int> seg[N]; const void solve(/*Armashka*/) { cin >> n >> t; while (n --) { int type; cin >> type; if (type == 1) { int a, b; cin >> a >> b; int l = a ^ (t * last), r = b ^ (t * last); if (l > r) swap(l, r); st.insert({cur + 1, {l, r}}); seg[++ cur] = {l, r}; } else if (type == 2) { int id; cin >> id; st.erase({id, seg[id]}); seg[id] = {0, 0}; -- cur; } else { int a, b, k, ans = 0; cin >> a >> b >> k; int l = a ^ (t * last), r = b ^ (t * last); if (l > r) swap(l, r); for (auto cur : st) { int x = cur.sd.ft, y = cur.sd.sd; if (max(x, l) <= min(y, r)) { int cnt = min(y, r) - max(x, l) + 1; if (cnt >= k) ++ ans; } } cout << ans << "\n"; last = ans; } } } signed main() { fast; //freopen("divide.in", "r", stdin); //freopen("divide.out", "w", stdout); int tt = 1; // cin >> tt; while (tt --) { solve(); } } /* 5 4 4 1 2 3 1 3 4 5 3 4 5 2 3 2 1 3 1 1 3 5 2 3 4 5 2 1 3 1 */
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