Submission #495503

#TimeUsernameProblemLanguageResultExecution timeMemory
495503syyBank (IZhO14_bank)C++17
100 / 100
109 ms16844 KiB
#pragma GCC optimize("O3,unroll-loops") #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; #define FOR(i, a, b) for(ll i = (ll)a; i <= (ll)b; i++) #define DEC(i, a, b) for(ll i = (ll)a; i >= (ll)b; i--) typedef pair<ll, ll> pi; typedef pair<pi, ll> pii; typedef pair<ll, pi> ipi; typedef pair<pi, pi> pipi; #define mp make_pair #define f first #define s second typedef vector<ll> vi; typedef vector<pi> vpi; typedef vector<pii> vpii; #define pb push_back #define pf push_front #define all(v) v.begin(), v.end() #define size(v) (ll) v.size() #define disc(v) sort(all(v)); v.resize(unique(all(v)) - v.begin()); #define memset(x, v) memset(x, v, sizeof x) #define INF (const ll) (1e9 + 100) #define LLINF (const ll) 1e18 #define mod (const ll) (1e9 + 7) #define fastio ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define sandybridge __attribute__((optimize("Ofast"), target("arch=sandybridge"))) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); //can be used by calling rng() or shuffle(A, A+n, rng) inline ll rand(ll x, ll y) { ++y; return (rng() % (y-x)) + x; } //inclusive /* Serve the people in order. However, need to loop by bitmask so order of notes is variable. cur[bm] = first index of person not served, extra[bm] = leftover total value of notes not used to serve ppl bm stores which notes we take. */ ll n, m, a[25], b[25], cur[(1<<20)], extra[(1<<20)]; int main() { fastio; cin >> n >> m; FOR(i, 0, n-1) cin >> a[i]; FOR(i, 0, m-1) cin >> b[i]; memset(cur, -1); memset(extra, -1); cur[0] = extra[0] = 0; FOR(bm, 0, (1<<m)-1) { FOR(note, 0, m-1) { if (!(bm & (1<<note))) continue; ll prebm = bm ^ (1<<note); if (cur[prebm] == -1) continue; else if (extra[prebm] + b[note] == a[cur[prebm]]) { cur[bm] = cur[prebm] + 1; extra[bm] = 0; } else if (extra[prebm] + b[note] < a[cur[prebm]]) { cur[bm] = cur[prebm]; extra[bm] = extra[prebm] + b[note]; } // if extra + current node > current person to serve, this bitmask is impossible alr, ignore } if (cur[bm] == n) return cout << "YES", 0; } cout << "NO"; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...