Submission #495011

#TimeUsernameProblemLanguageResultExecution timeMemory
495011VictorPapričice (COCI20_papricice)C++17
0 / 110
4 ms4940 KiB
// #pragma GCC target ("avx,avx2,fma") // #pragma GCC optimize ("Ofast,inline") // O1 - O2 - O3 - Os - Ofast // #pragma GCC optimize ("unroll-loops") #include <bits/stdc++.h> using namespace std; #define rep(i, a, b) for (int i = (a); i < (b); ++i) #define per(i, a, b) for (int i = (b - 1); i >= (a); --i) #define trav(a, x) for (auto &a : x) #define all(x) x.begin(), x.end() #define sz(x) x.size() #define pb push_back #define debug(x) cout << #x << " = " << x << endl #define umap unordered_map #define uset unordered_set typedef pair<int, int> ii; typedef pair<int, ii> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<vi> vvi; typedef long long ll; typedef pair<ll, ll> pll; typedef vector<ll> vll; typedef vector<pll> vpll; const int INF = 1'000'000'007; int n, ans = INF, sub_size[200001]; vi graph[200001]; set<int> cur, old; void pre(int u, int p) { sub_size[u] = 1; trav(v, graph[u]) if (v != p) { pre(v, u); sub_size[u]+=sub_size[v]; } } void dfs(int u, int p) { if (sz(cur)) { int p1 = sub_size[u]; auto it = cur.lower_bound((n - sub_size[u]) / 2 + sub_size[u]); if (it == cur.end()) --it; rep(i, 0, 2) { int p2 = *it - sub_size[u], p3 = n - p1 - p2; int mn = min(p1, min(p2, p3)), mx = max(p1, max(p2, p3)); ans = min(ans, mx - mn); if (it == cur.begin()) break; --it; } } if (sz(old)) { int p1 = sub_size[u]; auto it = old.lower_bound((n - sub_size[u]) / 2); if (it == old.end()) --it; rep(i, 0, 2) { int p2 = *it - sub_size[u], p3 = n - p1 - p2; int mn = min(p1, min(p2, p3)), mx = max(p1, max(p2, p3)); ans = min(ans, mx - mn); if (it == old.begin()) break; --it; } } if (u) cur.insert(sub_size[u]); trav(v, graph[u]) if (v != p) dfs(v, u); cur.erase(sub_size[u]); old.insert(sub_size[u]); } int main() { cin.tie(0)->sync_with_stdio(0); cin.exceptions(cin.failbit); cin >> n; rep(i, 1, n) { int u, v; cin >> u >> v; graph[--u].pb(--v); } pre(0, 0); dfs(0, 0); cout << ans << endl; return 0; }
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