Submission #493665

#	Time	Username	Problem	Language	Result	Execution time	Memory
493665		Fysty	Kitchen (BOI19_kitchen)	C++14	100 / 100	22 ms	1000 KiB

kitchen

#include <bits/stdc++.h>
#include <random>
#include <chrono>
using namespace std;
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize ("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<double,double> pdd;
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T> void _do(T x){cerr<<x<<"\n";}
template<typename T,typename ...U> void _do(T x,U ...y){cerr<<x<<", ";_do(y...);}
#define dbg(...) cerr<<#__VA_ARGS__<<" = ";_do(__VA_ARGS__);

const int MOD1=1e9+7;
const int MOD2=998244353;
const ll INF=3e18;
const ld PI=3.14159265358979323846;
ll gcd(ll a,ll b){if(b==0) return a; return gcd(b,a%b);}
ll fpow(ll a,ll b,ll m)
{
    if(!b) return 1;
    ll ans=fpow(a*a%m,b/2,m);
    return (b%2?ans*a%m:ans);
}
ll inv(ll a,ll m) {return fpow(a,m-2,m);}

#define MottoHayaku ios::sync_with_stdio(false);cin.tie(0);
//#define int ll
#define rep(i,n) for(int i=0;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define repk(i,m,n) for(int i=m;i<n;i++)
#define F first
#define S second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define uni(c) c.resize(distance(c.begin(),unique(c.begin(),c.end())))
#define unisort(c) sort(c.begin(),c.end()),uni(c)
const int N=301;
ll a[N],b[N],dp[N*N];
signed main()
{
    MottoHayaku
    ll n,m,k;
    cin>>n>>m>>k;
    bool can=1;
    ll suma=0,sumb=0;
    rep1(i,n)
    {
        cin>>a[i];
        if(a[i]<k) can=0;
        suma+=a[i];
    }
    rep1(i,m)
    {
        cin>>b[i];
        sumb+=b[i];
    }
    if(!can)
    {
        cout<<"Impossible";
        return 0;
    }
    rep1(j,sumb) dp[j]=-INF;
    rep1(i,m)
    {
        for(int j=sumb-b[i];j>=0;j--)
        {
            if(dp[j]==-INF) continue;
            dp[j+b[i]]=max(dp[j+b[i]],dp[j]+min(b[i],n));
        }
    }
    ll ans=-1;
    for(int i=suma;i<=sumb;i++)
    {
        if(dp[i]>=n*k)
        {
            ans=i;
            break;
        }
    }
    if(ans==-1) cout<<"Impossible";
    else cout<<ans-suma;
}

• Subtask 1: 9 / 9
• Subtask 2: 22 / 22
• Subtask 3: 20 / 20
• Subtask 4: 21 / 21
• Subtask 5: 28 / 28