Submission #493428

#TimeUsernameProblemLanguageResultExecution timeMemory
493428wiwihoKitchen (BOI19_kitchen)C++14
100 / 100
26 ms972 KiB
#include <bits/stdc++.h> #include <bits/extc++.h> #define StarBurstStream ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); #define iter(a) a.begin(), a.end() #define riter(a) a.rbegin(), a.rend() #define lsort(a) sort(iter(a)) #define gsort(a) sort(riter(a)) #define pb(a) push_back(a) #define eb(a) emplace_back(a) #define pf(a) push_front(a) #define ef(a) emplace_front(a) #define pob pop_back() #define pof pop_front() #define mp(a, b) make_pair(a, b) #define F first #define S second #define mt make_tuple #define gt(t, i) get<i>(t) #define tomax(a, b) ((a) = max((a), (b))) #define tomin(a, b) ((a) = min((a), (b))) #define topos(a) ((a) = (((a) % MOD + MOD) % MOD)) #define uni(a) a.resize(unique(iter(a)) - a.begin()) #define printv(a, b) {bool pvaspace=false; \ for(auto pva : a){ \ if(pvaspace) b << " "; pvaspace=true;\ b << pva;\ }\ b << "\n";} using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef unsigned long long ull; typedef long double ld; using pii = pair<int, int>; using pll = pair<ll, ll>; using pdd = pair<ld, ld>; using tiii = tuple<int, int, int>; const ll MOD = 998244353; const ll MAX = 2147483647; template<typename A, typename B> ostream& operator<<(ostream& o, pair<A, B> p){ return o << '(' << p.F << ',' << p.S << ')'; } ll ifloor(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a < 0) return (a - b + 1) / b; else return a / b; } ll iceil(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a > 0) return (a + b - 1) / b; else return a / b; } void nosol(){ cout << "Impossible\n"; exit(0); } const int SZ = 300; int main(){ StarBurstStream int n, m, k; cin >> n >> m >> k; vector<int> a(n + 1), b(m + 1); int sa = 0, sb = 0; for(int i = 1; i <= n; i++) cin >> a[i], sa += a[i]; for(int i = 1; i <= m; i++) cin >> b[i], sb += b[i]; if(k > m || sb < sa) nosol(); for(int i = 1; i <= n; i++) if(a[i] < k) nosol(); vector<ll> dp(SZ * m + 5, -MAX); dp[0] = 0; for(int i = 1; i <= m; i++){ for(int j = SZ * m; j >= b[i]; j--){ dp[j] = max(dp[j], dp[j - b[i]] + min(n, b[i])); } } for(int i = sa; i <= SZ * m; i++){ if(dp[i] < n * k) continue; cout << i - sa << "\n"; return 0; } nosol(); return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...