#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
using namespace std;
typedef long long ll;
typedef double db;
typedef vector<long long> vl;
typedef pair<long long, long long > pl;
const int N = 1e6 + 1;
#define po pop_back
#define pb push_back
#define mk make_pair
#define lw lower_bound
#define up upper_bound
#define ff first
#define ss second
#define boost ios_base::sync_with_stdio(); cin.tie(0); cout.tie(0);
#define MOD 1000000007
#define MAX 1e18
#define MIN -1e18
#define per(i,a,b) for(ll i=b;i>=a;i--)
#define con continue
#define freopen freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout);
#define PI 3.14159265358979323846264338327950288419716939937510582097494459230781640628
// typedef tree<ll , null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
// template< typename T>
// using indexed_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
ll n, m, ans, mid, mn, mx, cnt, sum, h1, h2, arr[3234567],arr1[1234567], sz, k, i, j, h, a, w, x, y, z,par[1234567];
bool used[1234567];
//ll dx[4]={-1,1,0,0},dy[4]={0,0,-1,1},c1[123][123];
//vector<ll> edge[1234567];
//ll jump[22][223456];
//ll lvl[1234567];
//ll bit[1234567];
//ll timer;
//ll st[1234567],endd[1234567];
//pl tr[1234567];
//ll dp[5005][5005];
ll power(ll base, ll val, ll mod) {
ll res = 1;
while (val) {
if (val % 2 == 1) {
res = res * base;
}
base = base * base;
base %= mod;
res %= mod;
val /= 2;
}
return res;
}
bool comp(pl x,pl y){
if(x.ff>y.ff)return true;
return false;
}
ll find(ll x){
if(x==par[x])return x;
else return par[x]=find(par[x]);
}
class A {
public:
static void funcA() {
cin>>n;
ll p[1234567],g[1234567],e[1234567];
for(int i=1;i<=n;i++){
ll pos,gold,energy;
cin>>pos>>gold>>energy;
p[i]=pos;
g[i]=g[i-1]+gold;
e[i]=e[i-1]+energy;
}
ll ans=0;
ll mx=MIN;
p[n+1]=MAX;
p[0]=MIN;
for(int i=1;i<=n;i++){
for(int j=i;j<=n;j++){
ll len = p[j]-p[i];
//cout<<p[i]<<" "<<p[j]<<" "<<len<<'\n';
if(len <= e[j]-e[i-1] && (p[j+1]-p[i]) > (e[j]-e[i-1]) && (p[j]-p[i-1]) > (e[j]-e[i-1])){
mx=max(mx,g[j]-g[i-1]);
}
}
}
cout<<mx<<'\n';
}
}lol;
void solve() {
A::funcA();
}
int main() {
ll T = 1;
//cin>>T;
boost;
while (T--) {
solve();
}
}
