Submission #492904

#	Time	Username	Problem	Language	Result	Execution time	Memory
492904		Biaz	Coin Collecting (JOI19_ho_t4)	C++17	37 / 100	33 ms	24140 KiB

joi2019_ho_t4

#include <bits/stdc++.h>
#define int long long
//#define double long double
#define Nanase_Kurumi_aka_menhera_chan_is_mine ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define pb push_back
#define pi pair<double,int>
#define ALL(i) i.begin(),i.end()
#define gcd(i,j) __gcd(i,j)
#define fi first
#define se second
#define eps 0.00000001
#define ist insert
#define DNE nullptr
//#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math")
//#pragma GCC optimize("O2")
int max(int x,int y){return x>=y?x:y;}
int min(int x,int y){return x>=y?y:x;}
using namespace std;
typedef int ll;
const int N=2005;
const int M=1000005;
const int MOD=1000000007;//998244353;
const int INF=1000000000000000000;//2147483647;

int n,ans;
pi p[N];
int dp[2*N][2*N];
inline void sol(){
    cin >>n;
    for (int i=1;i<=2*n;i++)
        cin >>p[i].fi>>p[i].se;
    sort(p+1,p+2*n+1);
    for (int i=1;i<=2*n;i++){
        dp[0][i]=dp[0][i-1]+abs(p[i].fi-i)+abs(2-p[i].se);
        dp[i][0]=dp[i-1][0]+abs(p[i].fi-i)+abs(1-p[i].se);
        for (int j=1;j<i;j++)
            dp[j][i-j]=min(dp[j-1][i-j]+abs(p[i].fi-j)+abs(1-p[i].se),dp[j][i-j-1]+abs(p[i].fi-(i-j))+abs(2-p[i].se));
    }
    cout <<dp[n][n];
}

signed main(){
    Nanase_Kurumi_aka_menhera_chan_is_mine
    int _=1;
    //cin >>_;
    while (_--) sol();
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 29 / 29
• Subtask 3: 0 / 63