Submission #492381

#TimeUsernameProblemLanguageResultExecution timeMemory
492381Mike4235Birthday gift (IZhO18_treearray)C++17
100 / 100
1119 ms93636 KiB
/*#pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") #pragma GCC target("avx,avx2,fma")*/ #include <bits/stdc++.h> #define for1(i,a,b) for (int i = a; i <= b; i++) #define for2(i,a,b) for (int i = a; i >= b; i--) #define int long long #define sz(a) (int)a.size() #define pii pair<int,int> #define pb push_back /* __builtin_popcountll(x) : Number of 1-bit __builtin_ctzll(x) : Number of trailing 0 */ const long double PI = 3.1415926535897932384626433832795; const int INF = 1000000000000000000; const int MOD = 1000000007; const int MOD2 = 1000000009; const long double EPS = 1e-6; using namespace std; int n, m, q; int a[200005], d[200005], up[200005][18]; pii res; set<int> id[200005], se[200005]; vector<int> g[200005]; void dfs(int u, int p) { for1(i,1,17) up[u][i] = up[up[u][i - 1]][i - 1]; for (auto v : g[u]) if (v != p) { d[v] = d[u] + 1; up[v][0] = u; dfs(v, u); } } int lca(int u, int v) { if (d[u] < d[v]) swap(u, v); for1(i,0,17) if ((d[u] - d[v]) & (1 << i)) u = up[u][i]; if (u == v) return u; for2(i,17,0) if (up[u][i] != up[v][i]) { u = up[u][i]; v = up[v][i]; } return up[u][0]; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); // freopen("cf.inp", "r", stdin); // freopen("cf.out", "w", stdout); cin >> n >> m >> q; for1(i,1,n - 1) { int a, b; cin >> a >> b; g[a].push_back(b); g[b].push_back(a); } dfs(1, 0); for1(i,1,m) { cin >> a[i]; id[a[i]].insert(i); } for1(i,1,m - 1) se[lca(a[i], a[i + 1])].insert(i); while (q--) { int op; cin >> op; if (op == 1) { int i, u; cin >> i >> u; id[a[i]].erase(i); if (i > 1) se[lca(a[i - 1], a[i])].erase(i - 1); if (i < m) se[lca(a[i], a[i + 1])].erase(i); a[i] = u; id[a[i]].insert(i); if (i > 1) se[lca(a[i - 1], a[i])].insert(i - 1); if (i < m) se[lca(a[i], a[i + 1])].insert(i); } else { int l, r, u; cin >> l >> r >> u; auto it = id[u].lower_bound(l); if (it != id[u].end() && *it <= r) { cout << *it << " " << *it << "\n"; continue; } auto it2 = se[u].lower_bound(l); if (it2 != se[u].end() && *it2 < r) { cout << *it2 << " " << *it2 + 1 << "\n"; continue; } cout << "-1 -1\n"; } } }
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