Submission #491207

#TimeUTC-0UsernameProblemLanguageResultExecution timeMemory
4912072021-11-30 18:08:12macktvzNafta (COI15_nafta)C++17
34 / 100
1000 ms141880 KiB
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
// the value of k that minimizes dp[p-1][k-1] + (p[i]-p[k-1])^2
// is <= k that minimizes dp[p-1][k-1] + (p[i+1]-p[k-1])^2
const int R = 2e3+1;
bool vis1[R][R];
bool vis2[R][R];
int id[R][R];
int grid[R][R];
int n,m;
int oil[R*R];
vector<int> dp_cur(R,0),dp_last(R,0);
vector<int> Li(R*R,R);
vector<int> Ri(R*R,-1);
int poil[R];
int dx[4] = {0,0,1,-1};
int dy[4] = {1,-1,0,0};
vector<vector<int>> bad(R,vector<int>(R,0));
int bit[R*R];
int ans[R];
void update(int i, int val) {
for (; i <= m; i+=i&(-i)) {
bit[i]+=val;
}
}
int qry(int i) {
 
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