Submission #49019

#	Time	Username	Problem	Language	Result	Execution time	Memory
49019		faishol27	Carnival (CEOI14_carnival)	C++14	20 / 100	110 ms	716 KiB

carnival

#include <bits/stdc++.h>
using namespace std;

#define PUB push_back
#define POB pop_back

int N, respon, cntSet, bykSet, parent[155];
bool isCheck[155][155];
vector<int>sameSet[155];

void init(){
    memset(isCheck, 0, sizeof isCheck);
    
    for(int i=1;i<155;i++){
        isCheck[i][i] = 1;
        parent[i] = i;
        sameSet[i].PUB(i);
    }

    cntSet = N;

    cout << N;
    for(int i=1;i<=N;i++){
        cout << " " << i;
    }
    cout << endl << flush;

    cin >> bykSet;
}

void moveSet(int ke, int dari){
    for(int elm:sameSet[dari]){
        parent[elm] = ke;
        sameSet[ke].PUB(elm);
    }

    sameSet[dari].clear();
}

void compressSet(){
    for(int i=1;i<=bykSet;i++){
        if(sameSet[i].empty()){
            for(int j=i+1;j<=N;j++){
                if(!sameSet[j].empty()){
                    for(int elm:sameSet[j]){
                        parent[elm] = i;
                        sameSet[i].PUB(elm);
                    }
                    sameSet[j].clear();
                    
                    break;
                }
            }
        }
    }
}

int main(){
    cin >> N;

    init();
    while(bykSet != cntSet){
        for(int i=1;i<=N;i++){
            if(sameSet[parent[i]].empty()) continue;

            for(int j=i+1;j<=N;j++){
                if(sameSet[parent[j]].empty()) continue;
                if(isCheck[parent[i]][parent[j]]) continue;

                isCheck[parent[i]][parent[j]] = 1;
                cout << 2 << " " << sameSet[parent[i]].front() << " " << sameSet[parent[j]].front() << endl << flush;
                cin >> respon;
                if(respon == 1){
                    moveSet(parent[i], parent[j]);
                    cntSet--;
                    break;
                }
            }
        }
    }

    compressSet();

    cout << 0;
    for(int i=1;i<=N;i++) cout << " " << parent[i];
    cout << endl << flush;
}

• Subtask 1: 4 / 20
• Subtask 2: 4 / 20
• Subtask 3: 4 / 20
• Subtask 4: 4 / 20
• Subtask 5: 4 / 20