| # | Time | Username | Problem | Language | Result | Execution time | Memory |
|---|---|---|---|---|---|---|---|
| 489958 | JerryLiu06 | Palembang Bridges (APIO15_bridge) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// https://oj.uz/problem/view/APIO15_bridge
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using db = double;
using str = string;
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
using vi = vector<int>;
using vb = vector<bool>;
using vl = vector<ll>;
using vd = vector<db>;
using vs = vector<str>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vpd = vector<pd>;
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(0);
#define FASTIOF ios_base::sync_with_stdio(false); fin.tie(0);
#define mp make_pair
#define f first
#define s second
#define sz(x) (int)(x).size()
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define sor(x) sort(all(x))
#define rsz resize
#define ins insert
#define ft front()
#define bk back()
#define pb push_back
#define pf push_front
#define lb lower_bound
#define ub upper_bound
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define F0R(i, a) FOR(i, 0, a)
#define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--)
#define R0F(i, a) ROF(i, 0, a)
#define EACH(a, x) for (auto& a : x)
ll cdiv(ll a, ll b) { return a / b + ((a ^ b) > 0 && a % b); }
ll fdiv(ll a, ll b) { return a / b - ((a ^ b) < 0 && a % b); }
template<class T> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }
template<class T> void remDup(vector<T>& v) { sor(v); v.erase(unique(all(v)), v.end()); }
const int MOD = 1e9 + 7;
const int MX = 5e4 + 10;
const ll INF = 1e18;
int K, N; vector<array<int, 2>> ed; vl ansPref, ansSuff;
vi genAns() {
vi res; res.pb(0);
priority_queue<int> L;
priority_queue<int, vi, greater<int>> R; // R contains the median
while (sz(L)) L.pop();
while (sz(R)) R.pop();
ll lsum = 0, rsum = 0;
int curMedian = 0;
F0R(i, sz(ed)) {
EACH(C, ed[i]) {
if (C >= curMedian) {
R.push(C); rsum += C;
}
else {
L.push(C); lsum += C;
}
}
if (sz(R) > sz(L)) {
L.push(R.top()); lsum += R.top();
rsum -= R.top(); R.pop();
curMedian = R.top();
}
if (sz(L) > sz(R)) {
R.push(L.top()); rsum += L.top();
lsum -= L.top(); L.pop();
curMedian = R.top();
}
res.pb(rsum - lsum);
}
return res;
}
int main() {
FASTIO;
cin >> K >> N;
ll ans = 0;
FOR(i, 1, N + 1) {
char C1, C2; int A, B;
cin >> C1 >> A >> C2 >> B;
if (C1 == C2) {
ans += abs(B - A);
}
else {
ed.pb({A, B});
}
}
sort(all(ed), [&](array<int, 2> a, array<int, 2> b) { return a[0] + a[1] < b[0] + b[1]; });
ansPref = genAns();
reverse(all(ed));
ansSuff = genAns();
if (K == 1) {
return cout << ans + ansPref[sz(ed)] + sz(ed) << "\n", 0;
}
ll res = INF;
F0R(i, sz(ed) + 1) {
ckmin(res, ans + ansPref[i] + ansSuff[sz(ed) - i] + sz(ed));
}
cout << res;
}