# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
487421 |
2021-11-15T13:05:09 Z |
leaked |
Boat (APIO16_boat) |
C++14 |
|
616 ms |
4300 KB |
#include <bits/stdc++.h>
#define f first
#define s second
#define m_p make_pair
#define pb push_back
#define vec vector
#define sz(x) (int)(x).size()
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define pw(x) (1LL<<(x))
#define fast_iati ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
using namespace std;
template<class T> bool umin(T &a,const T &b){return (a>b?a=b,1:0);}
template<class T> bool umax(T &a,const T &b){return (a<b?a=b,1:0);}
typedef long long ll;
typedef pair<int,int> pii;
const int M=1e9+7;
const int N=5e2+10;
void add(int &a,int b){
a+=b;
if(a>=M) a-=M;
else if(a<0) a+=M;
}
int mult(int a,int b){
return 1ll*a*b%M;
}
int binpow(int a,int b){
int ans=1;
while(b){
if(b&1) ans=mult(ans,a);
b>>=1;a=mult(a,a);
}
return ans;
}
int inv[N];
int gi(int x){
if(!inv[x]) inv[x]=binpow(x,M-2);
return inv[x];
}
int C(int k,int n){
if(k>n) return 0;
int ans=1;
for(int i=n-k+1;i<=n;i++) ans=mult(ans,i);
for(int i=1;i<=k;i++) ans=mult(ans,gi(i));
return ans;
}
signed main(){
fast_iati;
int n;
cin>>n;
vec<int>a(n),b(n);
vec<int> kek;
for(int i=0;i<n;i++) cin>>a[i]>>b[i],kek.pb(a[i]-1),kek.pb(b[i]);
kek.pb(0);sort(all(kek));kek.erase(unique(all(kek)),kek.end());
vec<vec<int>>dp(n+1,vec<int>(sz(kek)+1,0));
vec<int>ways(sz(kek));
vec<vec<int>>col(sz(kek),vec<int>(n+1,0));
for(int i=1;i<sz(kek);i++){
ways[i]=kek[i]-kek[i-1];
for(int j=1;j<=n;j++){
col[i][j]=C(j,ways[i]);
// cout<<"HELLO "<<i<<' '<<ways[i]<<' '<<j<<' '<<col[i][j]<<endl;
}
}
for(int j=0;j<sz(kek);j++) dp[0][j]=1;
for(int i=0;i<n;i++){
a[i]=lower_bound(all(kek),a[i]-1)-kek.begin()+1;
b[i]=lower_bound(all(kek),b[i])-kek.begin();
}
for(int i=0;i<n;i++){
for(int j=a[i];j<=b[i];j++){
for(int k=i;k>=0;k--){
if(a[k]>j || b[k]<j) break;
// cout<<"DEBUG "<<j<<' '<<k<<' '<<i<<' '<<col[j][i-k+1]<<endl;
add(dp[i+1][j],mult(col[j][i-k+1],dp[k][i-1]));
}
}
add(dp[i+1][0],1);
for(int j=1;j<sz(kek);j++) add(dp[i+1][j],dp[i+1][j-1]);
}
int ans=0;
for(int j=0;j<=sz(kek);j++) add(ans,dp[n][j]);
cout<<ans;
return 0;
}
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
616 ms |
4300 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
616 ms |
4300 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
10 ms |
484 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
616 ms |
4300 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |