제출 #484489

#제출 시각아이디문제언어결과실행 시간메모리
484489jhnah917Dragon 2 (JOI17_dragon2)C++14
100 / 100
3038 ms2636 KiB
#pragma GCC optimize("O3")
#pragma GCC target("avx,avx2")
#include <bits/stdc++.h>
using namespace std;
using ll = long long;

int N, M, Q, S[30000], E[30000];
alignas(32) ll X[30000], Y[30000];
alignas(32) ll Ax[30000], Ay[30000], Bx[30000], By[30000], Dir[30000];
struct{ ll x, y, c; } V[30000], A, B;

int main(){
    ios_base::sync_with_stdio(false); cin.tie(nullptr);
    cin >> N >> M;
    for(int i=0; i<N; i++) cin >> V[i].x >> V[i].y >> V[i].c, V[i].c--;
    cin >> A.x >> A.y >> B.x >> B.y;
    sort(V, V+N, [](auto a, auto b){ return a.c < b.c; });
    for(int i=0; i<N; i++) X[i] = V[i].x, Y[i] = V[i].y;
    memset(S, 0x3f, sizeof S);
    memset(E, 0xc0, sizeof E);
    for(int i=0; i<N; i++) S[V[i].c] = min(S[V[i].c], i), E[V[i].c] = max(E[V[i].c], i);
    cin >> Q;
    while(Q--){
        int a, b, res = 0; cin >> a >> b; a--; b--;
        int len = E[a] - S[a] + 1;
        for(int i=0; i<len; i++) Ax[i] = A.x - X[S[a]+i];
        for(int i=0; i<len; i++) Ay[i] = A.y - Y[S[a]+i];
        for(int i=0; i<len; i++) Bx[i] = B.x - X[S[a]+i];
        for(int i=0; i<len; i++) By[i] = B.y - Y[S[a]+i];
        for(int i=0; i<len; i++) Dir[i] = Ax[i]*By[i] - Ay[i]*Bx[i];
        for(int i=0; i<len; i++){
            for(int j=S[b]; j<=E[b]; j++){
                const ll dX = X[j] - X[S[a]+i], dY = Y[j] - Y[S[a]+i];
                const ll cA = dX*Ay[i] - dY*Ax[i], cB = dX*By[i] - dY*Bx[i];
                if(Dir[i] >= 0) res += cA <= 0 && cB >= 0;
                else res += cA >= 0 && cB <= 0;
            }
        }
        cout << res << "\n";
    }
}
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