제출 #483961

#제출 시각아이디문제언어결과실행 시간메모리
483961PoPularPlusPlus경주 (Race) (IOI11_race)C++17
0 / 100
3 ms5196 KiB
#include "race.h"
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ull unsigned long long 
#define pb(e) push_back(e)
#define sv(a) sort(a.begin(),a.end())
#define sa(a,n) sort(a,a+n)
#define mp(a,b) make_pair(a,b)
#define vf first
#define vs second
#define ar array
#define all(x) x.begin(),x.end()
const int inf = 0x3f3f3f3f;
const int mod = 1000000007; 
const double PI=3.14159265358979323846264338327950288419716939937510582097494459230;
bool remender(ll a , ll b){return a%b;}

const int N = 200002;
vector<pair<int,int>> adj[N];
int k;
int siz[N];
bool vis[N];
int cnt[N];
int ans;

void subtree(int node , int par = -1){
	siz[node] = 1;
	for(auto i : adj[node]){
		if(!vis[i.vf] && i.vf != par){
			subtree(i.vf , node);
			siz[node] += siz[i.vf];
		}
	}
}

int get(int node , int par , int need){
	for(auto i : adj[node]){
		if(!vis[i.vf] && i.vf != par && siz[i.vf] > need){
			return get(i.vf , node , need);
		}
	}
	return node;
}

void cal(int node , int par , int depth , int cur , int fill){
	if(cur > k)return;
	if(fill){
		ans = min(ans , depth + cnt[k - cur]);
	}
	else {
		cnt[cur] = min(cnt[cur] , depth);
	}
	for(auto i : adj[node]){
		if(!vis[i.vf] && i.vf != par){
			cal(i.vf , node , depth + 1 , i.vs + cur , fill);
		}
	}
}

void clear(int node , int par , int cur){
	if(cur > k)return;
	cnt[cur] = 1e9;
	for(auto i : adj[node]){
		if(i.vf!=par && !vis[i.vf]){
			clear(i.vf ,node , cur + i.vs);
		}
	}
}

void centriod(int node){
	subtree(node);
	int cen = get(node , -1 , siz[node]/2);
	cnt[0] = 0;
	for(auto i : adj[cen]){
		cal(i.vf , cen , 1 , i.vs , 1);
		cal(i.vf , cen , 1 , i.vs , 0);
	}
	cout << cen << ' ' << ans << '\n';
	for(auto i : adj[cen]){
		clear(i.vf , node , i.vs);
	}
	vis[cen] = 1;
	for(auto i : adj[cen]){
		if(!vis[i.vf]){
			centriod(i.vf);
		}
	}
}

int best_path(int n , int k1 , int h[][2], int l[]){
	for(int i = 0; i < n-1; i++){
		adj[h[i][0]].pb(mp(h[i][1] , l[i]));
		adj[h[i][1]].pb(mp(h[i][0] , l[i]));
	}
	k = k1;
	memset(vis,0,sizeof vis);
	for(int i = 0; i <= k; i++){
		cnt[i] = 1e9;
	}
	ans = 1e9;
	centriod(0);
	return(ans == 1e9 ? -1 : ans);
}
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