Submission #483738

#	Time	Username	Problem	Language	Result	Execution time	Memory
483738		kawaii	Peru (RMI20_peru)	C++17	0 / 100	1 ms	468 KiB

peru

#include <bits/stdc++.h>
using namespace std;
//define int long long

long long mod = 1e9 + 7, ans = 0;
int n, m, k, a[2500001], l2[2500001], mx[2500001][22];
deque<pair<int, int> > dq;

long long mul(long long x, long long y){
    if(y == 0) return 1;
    long long ans = mul(x, y / 2);
    if(y % 2 == 0) return (ans * ans) % mod;
    else return (((ans * ans) % mod) * x) % mod;
}

int solve(int n, int k, int* a){
    for(int i = 0; i <= n; i++){
        for(int j = 1; (1 << j) <= n; j++){
            mx[i][j] = max(mx[i][j - 1], mx[i + (1 << (j - 1))][j - 1]);
        }
    }
    dq.push_back(make_pair(0, 0));
    for(int i = 1; i <= n; i++){
        if(dq.size() == 0){
            dq.push_back(make_pair(a[i], i));  
            ans = (ans + (long long) a[i] * mul(23, n - i)) % mod;
        }
        else{
            int q = dq.front().first;
            pair<int, int> t;
            while(dq.size() > 0 && dq.front().first == q){
                t = dq.front();
                dq.pop_front();
            }
            dq.push_front(t);
            while(dq.size() > 0 && i - dq.front().second > k) dq.pop_front();
            t = dq.front();
            int c = l2[i - t.second];
            dq.push_back(make_pair(((long long) t.first + max(mx[t.second][c], mx[i - (1 << c) + 1][c])) % mod, i));
            ans = (ans + (long long) dq.back().first * mul(23, n - i)) % mod; 
        }
    }
    return ans;
} 

• Subtask 1: 0 / 18
• Subtask 2: 0 / 31
• Subtask 3: 0 / 51