이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
//#pragma GCC optimize ("O3")
//#pragma GCC target ("sse4")
#ifndef LOCAL
#define cerr if(false) cerr
#endif
#define endl "\n"
#define all(x) (x).begin(), (x).end()
#define forn(i, n) for(int i = 0; i < n; i ++)
#define revn(i, n) for(int i = n - 1; i >= 0; i --)
typedef long long ll;
template<class T, template<class T2, class A=allocator<T2> > class cont> inline ostream &operator <<(ostream &out, const cont<T> &x) { for(const auto &it : x) { out << it << " ";} return out;}
template<class T, template<class T2, class A=allocator<T2> > class cont> inline istream &operator >>(istream &in, cont<T> &x) { for(auto &it : x) { in >> it;} return in;}
template<class T, class T2> inline ostream &operator <<(ostream &out, const pair<T, T2> &x) { out << x.first << " " << x.second; return out;}
template<class T, class T2> inline istream &operator >>(istream &in, pair<T, T2> &x) { in >> x.first >> x.second; return in;}
template<class T, class T2> inline bool chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; }
template<class T, class T2> inline bool chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; }
const ll mod = 1e9 + 7;
const int MAX_N = 5010;
bool tab1[MAX_N][MAX_N], tab2[MAX_N][MAX_N];
bool onRow[MAX_N], onCol[MAX_N];
int n, m, k;
map<int, bool> up, lft;
ll fpow(ll x, ll p) {
if(p == 0) {
return 1;
}
ll ans = fpow(x, p / 2ll);
ans = (ans * ans) % mod;
if(p & 1) {
return (ans * x) % mod;
} else {
return ans;
}
}
bool okUp = true, okLeft = true;
signed main() {
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
cin >> n >> m >> k;
ll ret = 0;
forn(i, k) {
int a, b;
char c;
cin >> c >> a >> b;
int offset = (c == '+');
if(up.find(b) != up.end()) {
if(up[b] != ((offset + a) & 1)) {
okUp = false;
}
} else {
up[b] = ((offset + a) & 1);
}
if(lft.find(a) != lft.end()) {
if(lft[a] != ((offset + b) & 1)) {
okLeft = false;
}
} else {
lft[a] = ((offset + b) & 1);
}
}
if(okUp) {
ret = (ret + fpow(2, m - up.size())) % mod;
}
if(okLeft) {
ret = (ret + fpow(2, n - lft.size())) % mod;
}
if(okLeft && okUp) {
if(k == 0) {
ret = (ret - 2 + mod) % mod;
} else {
ret = (ret - 1 + mod) % mod;
}
}
cout << ret << endl;
return 0;
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |