This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e5 + 5;
const int mod = 1e9 + 7;
int Add(int x, int y)
{
return x + y >= mod ? x + y - mod : x + y;
}
int Sub(int x, int y)
{
return x - y < 0 ? x - y + mod : x - y;
}
int Mul(int x, int y)
{
return 1ll * x * y % mod;
}
int BinPow(int n, long long k)
{
int ans = 1, cur = n;
while(k)
{
if(k & 1)
{
ans = Mul(ans, cur);
}
cur = Mul(cur, cur);
k >>= 1;
}
return ans;
}
int fact[MAXN], ifact[MAXN];
int C(int k, int n)
{
if(k > n or k < 0)
{
return 0;
}
return Mul(fact[n], Mul(ifact[k], ifact[n - k]));
}
void MulM(vector <vector <int> > &A, vector <vector <int> > B)
{
int n = A.size();
vector <vector <int> > C(n, vector <int> (n, 0));
for(int i = 0; i < n; i++)
{
for(int j = 0; j < n; j++)
{
for(int k = 0; k < n; k++)
{
C[i][j] = Add(C[i][j], Mul(A[i][k], B[k][j]));
}
}
}
swap(A, C);
}
void BinPowM(vector <vector <int> > &A, long long k)
{
int n = A.size();
vector <vector <int> > B(n, vector <int> (n));
for(int i = 0; i < n; i++)
{
B[i][i] = 1;
}
while(k)
{
if(k & 1)
{
MulM(B, A);
}
MulM(A, A);
k >>= 1;
}
swap(A, B);
}
int m, x;
int a[] = {10, 8, 18, 28, 9, 21, 6, 24, 23, 29};
long long n, k;
int main()
{
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
fact[0] = 1;
for(int i = 1; i < MAXN; i++)
{
fact[i] = Mul(fact[i - 1], i);
}
ifact[MAXN - 1] = BinPow(fact[MAXN - 1], mod - 2);
for(int i = MAXN - 2; i >= 0; i--)
{
ifact[i] = Mul(ifact[i + 1], i + 1);
}
cin >> m >> n >> k >> x;
if(m == 1)
{
vector <vector <int> > DP(6, vector <int> (6, 0));
vector <vector <int> > Cnt(6, vector <int> (6, 0));
DP[0][0] = 1;
for(int i = 0; i < 6; i++)
{
if(i < 5)
{
Cnt[i][i + 1] = 5 - i;
}
if(i > 0)
{
Cnt[i][i - 1] = i;
}
}
BinPowM(Cnt, k);
MulM(DP, Cnt);
for(int i = 0; i < 6; i++)
{
DP[0][i] = Mul(DP[0][i], BinPow(C(i, 5), mod - 2));
}
vector <vector <int> > Ans(10, vector <int> (10, 0));
vector <vector <int> > NDP(10, vector <int> (10, 0));
Ans[0][x] = 1;
for(int i = 0; i < 10; i++)
{
for(int j = 0; j < 10; j++)
{
NDP[i][j] = DP[0][__builtin_popcount(a[i] ^ a[j])];
}
}
BinPowM(NDP, n / k);
MulM(Ans, NDP);
n %= k;
for(int i = 0; i < 6; i++)
{
for(int j = 0; j < 6; j++)
{
DP[i][j] = 0;
Cnt[i][j] = 0;
}
}
DP[0][0] = 1;
for(int i = 0; i < 6; i++)
{
if(i < 5)
{
Cnt[i][i + 1] = 5 - i;
}
if(i > 0)
{
Cnt[i][i - 1] = i;
}
}
BinPowM(Cnt, n);
MulM(DP, Cnt);
for(int i = 0; i < 6; i++)
{
DP[0][i] = Mul(DP[0][i], BinPow(C(i, 5), mod - 2));
}
for(int i = 0; i < 10; i++)
{
for(int j = 0; j < 10; j++)
{
NDP[i][j] = DP[0][__builtin_popcount(a[i] ^ a[j])];
}
}
MulM(Ans, NDP);
for(int i = 0; i < 10; i++)
{
cout << Ans[0][i] << '\n';
}
}
else
{
vector <vector <int> > DP(11, vector <int> (11, 0));
vector <vector <int> > Cnt(11, vector <int> (11, 0));
DP[0][0] = 1;
for(int i = 0; i < 11; i++)
{
if(i < 10)
{
Cnt[i][i + 1] = 10 - i;
}
if(i > 0)
{
Cnt[i][i - 1] = i;
}
}
BinPowM(Cnt, k);
MulM(DP, Cnt);
for(int i = 0; i < 11; i++)
{
DP[0][i] = Mul(DP[0][i], BinPow(C(i, 10), mod - 2));
}
vector <vector <int> > Ans(100, vector <int> (100, 0));
vector <vector <int> > NDP(100, vector <int> (100, 0));
Ans[0][x] = 1;
for(int i = 0; i < 100; i++)
{
for(int j = 0; j < 100; j++)
{
int t1 = i / 10, t2 = j / 10, t3 = i % 10, t4 = j % 10;
NDP[i][j] = DP[0][__builtin_popcount(a[t1] ^ a[t2]) + __builtin_popcount(a[t3] ^ a[t4])];
}
}
BinPowM(NDP, n / k);
MulM(Ans, NDP);
n %= k;
for(int i = 0; i < 11; i++)
{
for(int j = 0; j < 11; j++)
{
DP[i][j] = 0;
Cnt[i][j] = 0;
}
}
DP[0][0] = 1;
for(int i = 0; i < 11; i++)
{
if(i < 10)
{
Cnt[i][i + 1] = 10 - i;
}
if(i > 0)
{
Cnt[i][i - 1] = i;
}
}
BinPowM(Cnt, n);
MulM(DP, Cnt);
for(int i = 0; i < 11; i++)
{
DP[0][i] = Mul(DP[0][i], BinPow(C(i, 10), mod - 2));
}
for(int i = 0; i < 100; i++)
{
for(int j = 0; j < 100; j++)
{
int t1 = i / 10, t2 = j / 10, t3 = i % 10, t4 = j % 10;
NDP[i][j] = DP[0][__builtin_popcount(a[t1] ^ a[t2]) + __builtin_popcount(a[t3] ^ a[t4])];
}
}
MulM(Ans, NDP);
for(int i = 0; i < 100; i++)
{
cout << Ans[0][i] << '\n';
}
}
}
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