Submission #480714

#TimeUsernameProblemLanguageResultExecution timeMemory
480714hidden1Toll (BOI17_toll)C++14
100 / 100
238 ms32964 KiB
#include <bits/stdc++.h> using namespace std; //#pragma GCC optimize ("O3") //#pragma GCC target ("sse4") #define endl "\n" typedef long long ll; template<class T, class T2> inline ostream &operator <<(ostream &out, const pair<T, T2> &x) { out << x.first << " " << x.second; return out;} template<class T, class T2> inline istream &operator >>(istream &in, pair<T, T2> &x) { in >> x.first >> x.second; return in;} template<class T, class T2> inline bool chkmax(T &x, const T2 &y) { return x < y ? x = y, 1 : 0; } template<class T, class T2> inline bool chkmin(T &x, const T2 &y) { return x > y ? x = y, 1 : 0; } const ll mod = 1e15 + 7; #ifndef LOCAL #define cerr if(false) cerr #endif typedef vector<vector<ll> > mat; const ll MAX_N = 1e5 + 10; ll n, m, k, q; mat mult(const mat &a, const mat &b) { mat ret = mat(k, vector<ll>(k, mod)); if(a.empty()) { return b; } if(b.empty()) { return a; } for(ll i = 0; i < k; i ++) { for(ll j = 0; j < k; j ++) { for(ll mid = 0; mid < k; mid ++) { chkmin(ret[i][j], a[i][mid] + b[mid][j]); } } } return ret; } vector<pair<ll, ll> > g[MAX_N]; mat prec[MAX_N]; mat tree[4 * MAX_N]; void build(int curr, int l, int r) { if(l == r) { tree[curr] = prec[l]; return; } int m = (l + r) / 2ll; build(curr * 2, l, m); build(curr * 2 + 1, m + 1, r); tree[curr] = mult(tree[curr * 2], tree[curr * 2 + 1]); } mat quer(int curr, int l, int r, int ql, int qr) { if(ql <= l && r <= qr) { return tree[curr]; } else if(ql > r || l > qr) { return {}; } int m = (l + r) / 2ll; return mult( quer(curr * 2, l, m, ql, qr), quer(curr * 2 + 1, m + 1, r, ql, qr) ); } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); cin >> k >> n >> m >> q; for(ll i = 0; i < m; i ++) { ll a, b, c; cin >> a >> b >> c; g[a].push_back({b, c}); } for(ll i = 0; i < n; i += k) { prec[i / k] = mat(k, vector<ll>(k, mod)); for(ll j = i; j < i + k; j ++) { for(auto it : g[j]) { chkmin(prec[i / k][j % k][it.first % k], it.second); } } } build(1, 0, MAX_N - 1); while(q --) { ll a, b; cin >> a >> b; if(a / k >= b / k) { cout << -1 << endl; continue; } mat ret = quer(1, 0, MAX_N - 1, a / k, b / k - 1); if(ret[a % k][b % k] == mod) { cout << -1 << endl; } else { cout << ret[a % k][b % k] << endl; } } return 0; }
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