Submission #477664

#	Time	Username	Problem	Language	Result	Execution time	Memory
477664		HappyPacMan	Minerals (JOI19_minerals)	C++14	40 / 100	58 ms	6564 KiB

minerals

#include "minerals.h"
#include <bits/stdc++.h>
using namespace std;

int curr = 0;

bool change(int u){
    int nxt = Query(u);
    bool res = (nxt != curr);
    curr = nxt;
    return res;
}

void Solve(int N){
    mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
    vector<int> group[2];
    for(int i=1;i<=2*N;i++) group[change(i)].emplace_back(i);
    shuffle(group[0].begin(),group[0].end(),rng);
    int l[N],r[N];
    vector<int> mid[N];
    for(int i=0;i<N;i++){
        l[i] = 0;
        r[i] = N-1;
        mid[r[i] - (382*(r[i]-l[i]+1)/1000)].emplace_back(i);
    }
    // for(auto u : group[0]) cout << u << ' '; cout << '\n';
    // for(auto u : group[1]) cout << u << ' '; cout << '\n';
    int found = 0;
    while(found < N){
        // for(int i=0;i<N;i++) cout << l[i] << ' '; cout << '\n';
        // for(int i=0;i<N;i++) cout << r[i] << ' '; cout << '\n'; cout << '\n';
        int prefix[N];
        memset(prefix,0,sizeof(prefix));
        for(int i=0;i<N;i++){
            if(l[i] != r[i]){
                prefix[l[i]]++;
                if(r[i]+1 < N) prefix[r[i]+1]--;
            }
        }
        for(int i=1;i<N;i++) prefix[i] += prefix[i-1];
        for(int i=N-1;i>=0;i--){
            if(!prefix[i]) continue;
            change(group[0][i]);
            vector<int> curr = mid[i];
            mid[i].clear();
            for(auto u : curr){
                bool nxt = change(group[1][u]);
                if(nxt){
                    l[u] = i;
                    int nxm = l[u] + (618*(r[u]-l[u]+1)/1000);
                    if(nxm == r[u]) nxm--;
                    // cout << "nxm 1 : " << group[0][i] << ' ' << group[1][u] << ' ' << nxm << ' ' << r[u] << ' ' << l[u] << '\n';
                    if(l[u] == r[u]){
                        Answer(group[0][l[u]],group[1][u]);
                        found++;
                    }else mid[nxm].emplace_back(u);
                }else{
                    r[u] = i-1;
                    int nxm = r[u] - (382*(r[u]-l[u]+1)/1000);
                    // cout << "nxm 2 : " << group[0][i] << ' ' << group[1][u] << ' ' << nxm << ' ' << r[u] << ' ' << l[u] << '\n';
                    if(l[u] == r[u]){
                        Answer(group[0][l[u]],group[1][u]);
                        found++;
                    }else mid[nxm].emplace_back(u);
                }
            }
        }
        memset(prefix,0,sizeof(prefix));
        for(int i=0;i<N;i++){
            if(l[i] != r[i]){
                prefix[l[i]]++;
                if(r[i]+1 < N) prefix[r[i]+1]--;
            }
        }
        for(int i=1;i<N;i++) prefix[i] += prefix[i-1];
        for(int i=0;i<N;i++){
            if(!prefix[i]) continue;
            change(group[0][i]);
            vector<int> curr = mid[i];
            mid[i].clear();
            for(auto u : curr){
                bool nxt = change(group[1][u]);
                if(nxt){
                    l[u] = i+1;
                    int nxm = l[u] + (382*(r[u]-l[u]+1)/1000);
                    // cout << "nxm 3 : " << group[0][i] << ' ' << group[1][u] << ' ' << nxm << ' ' << r[u] << ' ' << l[u] << '\n';
                    if(l[u] == r[u]){
                        Answer(group[0][l[u]],group[1][u]);
                        found++;
                    }else mid[nxm].emplace_back(u);
                }else{
                    r[u] = i;
                    int nxm = r[u] - (618*(r[u]-l[u]+1)/1000);
                    if(nxm == l[u]) nxm++;
                    // cout << "nxm 4 : " << group[0][i] << ' ' << group[1][u] << ' ' << nxm << ' ' << r[u] << ' ' << l[u] << '\n';
                    if(l[u] == r[u]){
                        Answer(group[0][l[u]],group[1][u]);
                        found++;
                    }else mid[nxm].emplace_back(u);
                }
            }
        }
    }
}   

• Subtask 1: 6 / 6
• Subtask 2: 25 / 25
• Subtask 3: 9 / 9
• Subtask 4: 0 / 30
• Subtask 5: 0 / 5
• Subtask 6: 0 / 5
• Subtask 7: 0 / 5
• Subtask 8: 0 / 5
• Subtask 9: 0 / 10