Submission #47727

#	Time	Username	Problem	Language	Result	Execution time	Memory
47727		_EmanuelNrx_	Fortune Telling 2 (JOI14_fortune_telling2)	C++14	4 / 100	234 ms	18644 KiB

fortune_telling2

#include <bits/stdc++.h>
using namespace std;

const int DIM = 600005;

pair<int, int> seg[DIM], num[DIM]; vector<int> aux, lst[DIM];
int sgt[DIM << 2], bit[DIM], arr[DIM], pos[DIM];

inline bool cmp(pair<int, int> sg1, pair<int, int> sg2)
{
    return max(sg1.first, sg1.second) < max(sg2.first, sg2.second);
}

void update(int nod, int lef, int rig, int pos, int val)
{
    if (lef == rig)
        sgt[nod] = max(sgt[nod], val);
    else {
        int mid = (lef + rig) >> 1;
        
        if (pos <= mid)
            update(nod << 1, lef, mid, pos, val);
        else
            update(nod << 1 | 1, mid + 1, rig, pos, val);
        
        sgt[nod] = max(sgt[nod << 1], sgt[nod << 1 | 1]);
    }
}

int query(int nod, int lef, int rig, int _lef, int _rig)
{
    if (_lef <= lef and rig <= _rig)
        return sgt[nod];
    else {
        int mid = (lef + rig) >> 1;
        
        if (_rig <= mid)
            return query(nod << 1, lef, mid, _lef, _rig);
        if (_lef >  mid)
            return query(nod << 1 | 1, mid + 1, rig, _lef, _rig);
        
        return max(query(nod << 1, lef, mid, _lef, _rig),
                   query(nod << 1 | 1, mid + 1, rig, _lef, _rig));
    }
}

void update(int pos, int n)
{
    for (int i = pos; i <= n; i += (i & -i))
        bit[i] ^= 1;
}

int query(int pos, int x = 0)
{
    for (int i = pos; i >= 1; i -= (i & -i))
        x ^= bit[i];
    return x;
}

long long bruteForce(int n, int k)
{
    for (int i = 1; i <= n; ++i)
        cin >> seg[i].first >> seg[i].second;
    
    while (k--) {
        int x;
        cin >> x;
        
        for (int i = 1; i <= n; ++i)
            if (seg[i].first <= x)
                swap(seg[i].first, seg[i].second);
    }
    
    long long ans = 0;
    for (int i = 1; i <= n; ++i)
        ans += seg[i].first;
    
    return ans;
}

long long solve(int n, int k)
{
    long long ans = 0;
    for (int i = 1; i <= n; ++i) {
        cin >> seg[i].first >> seg[i].second;
        
        if (seg[i].first == seg[i].second) {
            ans += seg[i--].first; --n;
            continue;
        }
        
        aux.push_back(seg[i].first);
        aux.push_back(seg[i].second);
    }
    
    for (int i = 1; i <= k; ++i) {
        cin >> pos[i];
        aux.push_back(pos[i]);
    }
    
    sort(aux.begin(), aux.end());
    aux.resize(unique(aux.begin(), aux.end()) - aux.begin()); int m = (int) aux.size();
    
    sort(seg + 1, seg + n + 1, cmp);
    
    for (int i = 1; i <= n; ++i) {
        num[i] = seg[i];
        seg[i].first = (int) (lower_bound(aux.begin(), aux.end(), seg[i].first) - aux.begin() + 1);
        seg[i].second = (int) (lower_bound(aux.begin(), aux.end(), seg[i].second) - aux.begin() + 1);
    }
    
    for (int i = 1; i <= k; ++i) {
        pos[i] = (int) (lower_bound(aux.begin(), aux.end(), pos[i]) - aux.begin() + 1);
        update(1, 1, m, pos[i], i);
    }
    
    for (int i = 1; i <= n; ++i) {
        int a = seg[i].first, b = seg[i].second;
        
        if (a > b)
            swap(a, b);
        lst[query(1, 1, m, a, b - 1)].push_back(i);
    }
    
    for (; k >= 0; --k) {
        for (int x : lst[k]) {
            bool val = query(x);
            if (k) val ^= (num[x].second > num[x].first);
            ans += val ? num[x].second : num[x].first;
        }
        
        int psx = 0;
        for (int lef = 1, rig = n; lef <= rig; ) {
            int mid = (lef + rig) >> 1;
            
            if (seg[mid].second <= pos[k])
                lef = mid + 1, psx = mid;
            else
                rig = mid - 1;
        }
        
        if (psx != 0)
            update(1, n), update(psx + 1, n);
    }
    
    return ans;
}

int main(void)
{
    //  freopen("test.in", "r", stdin);
    //  freopen("test.out", "w", stdout);
    
    int n, k;
    cin >> n >> k;
    
    if (n <= 1000 && k <= 1000)
        cout << bruteForce(n, k) << endl;
    else
        cout << solve(n, k) << endl;
    
    return 0;
}

• Subtask 1: 4 / 4
• Subtask 2: 0 / 31
• Subtask 3: 0 / 65