This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#include "keys.h"
using namespace std;
#define fir first
#define sec second
const int maxn = 3e5 + 5;
int n,m;
// DSU
int par[maxn]; // root of group
int sz[maxn]; // size of group
int find(int x)
{
if (par[x]==x) return x;
return par[x]=find(par[x]);
}
bool have[maxn],vis[maxn];
bool mk[maxn]; // mark wheter
int q[maxn];
int r[maxn]; // room keys;
vector<pair<int,int>> conn[maxn]; // connections and the key value that is needed
vector<int> vec[maxn];
vector<int> ans; // (to find) the number of rooms that can be visited if start from i
int bfs(int s, bool flag = false)
{
int hd,tl;
hd = 1; tl = 0;
int ret = 0;
q[++tl] = s;
vis[s] = 1;
while (hd<=tl)
{
int x = q[hd]; hd++;
if (!have[r[x]])
{
while (!vec[r[x]].empty())
{
int y=vec[r[x]].back();
if (find(y)!=s) ret = find(y);
if (!vis[y])
{
q[++tl] = y;
vis[y] = 1;
}
vec[r[x]].pop_back();
}
have[r[x]]=1;
}
for (pair<int,int> A : conn[x])
{
int y = A.fir;
if (have[A.sec])
{
if (find(y)!=s) ret = find(y);
if (!vis[y])
{
q[++tl] = y;
vis[y] = 1;
}
}
else vec[A.sec].push_back(y);
}
if (ret) break;
}
for (int i=1;i<=tl;i++) vis[q[i]] = 0;
for (int i=1;i<hd;i++)
{
int x = q[i];
have[r[x]] = 0;
for (pair<int,int> A : conn[x])
vec[A.sec].clear();
}
if (flag)
{
for (int i=1;i<=tl;i++)
ans[q[i]-1] = tl;
}
return ret;
}
vector<int> find_reachable(vector<int> R,vector<int> U,vector<int> V, vector<int> C)
{
n = R.size(); m = U.size();
// initializing the DSU
for (int i=1;i<=n;i++)
{
par[i] = i;
sz[i] = 1;
}
// storing the room keys (1-based)
for (int i=0;i<n;i++) r[i+1] = R[i] + 1;
//initializing the answer array
ans = vector<int> (n,n+1);
// converting to the connection list (1-based)
for (int i=0;i<m;i++)
{
int x,y,z;
x=U[i]+1; y=V[i]+1; z=C[i]+1;
conn[x].push_back({y,z});
conn[y].push_back({x,z});
}
// maximum log(n) times
while (true)
{
bool flag = false;
// set roots visit state initially to 0
for (int i=1;i<=n;i++) mk[i] = false;
for (int i=1;i<=n;i++)
{
// starting a BFS from a root that is not visited yet
if (find(i)==i && !mk[i])
{
int t = bfs(i);
if (t>0)
{
par[i] = t;
mk[t] = true;
flag = true;
}
else mk[i] = true;
}
}
if (!flag) break;
}
for (int i=1;i<=n;i++)
{
// only bfs to the roots
if (find(i)==i) bfs(i,1);
}
// formatting the answer: ans[i] is the number of rooms vis
int mn = n+1;
for (int i=1;i<=n;i++) mn = min(mn,ans[i-1]);
for (int i=1;i<=n;i++)
{
if (mn==ans[i-1]) ans[i-1] = 1;
else ans[i-1] = 0;
}
return ans;
}
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