이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "supertrees.h"
#include <bits/stdc++.h>
using namespace std;
struct DSU {
vector<int> pai, rank, sz;
DSU(int n) {
pai.resize(n);
rank.assign(n, 0);
sz.assign(n, 1);
iota(pai.begin(), pai.end(), 0);
}
int findSet(int v) {
return v == pai[v] ? v : pai[v] = findSet(pai[v]);
}
int join(int a, int b) {
a = findSet(a);
b = findSet(b);
if(a == b) return 0;
else if(rank[a] > rank[b]) swap(a, b);
pai[a] = b;
rank[b] += rank[a] == rank[b];
sz[b] += sz[a];
return 1;
}
};
int construct(vector<vector<int>> p) {
int n = p.size();
for(int u = 0; u < n; ++u) {
for(int v = 0; v < n; ++v) {
if(p[u][v] == 3)
return 0;
}
}
vector<int> id(n, -1);
auto g = vector<vector<int>>(n, vector<int>(n, 0));
DSU dsu(n), w(n);
int t = 0;
for(int v = 0; v < n; ++v) {
if(id[v] != -1) continue;
queue<int> q;
vector<int> comp;
id[v] = t;
q.push(v);
while(!q.empty()) {
int u = q.front();
q.pop();
comp.push_back(u);
for(int v = 0; v < n; ++v) {
if(p[u][v] == 1) dsu.join(u, v);
if(id[v] != -1 || p[u][v] == 0) continue;
id[v] = t;
q.push(v);
}
}
for(int i = 0; i < (int)comp.size(); ++i) {
int u = comp[i];
for(int j = i + 1; j < (int)comp.size(); ++j) {
int v = comp[j];
int U = dsu.findSet(u);
int V = dsu.findSet(v);
if(U == V && p[u][v] != 1 || U != V && p[u][v] != 2) return 0;
}
}
for(int i = 0; i < (int)comp.size(); ++i) {
int u = comp[i];
for(int j = i + 1; j < (int)comp.size(); ++j) {
int v = comp[j];
int U = dsu.findSet(u);
int V = dsu.findSet(v);
if(U == V) g[u][v] = g[v][u] = w.join(u, v);
}
}
vector<int> cycle;
for(int v : comp) if(dsu.findSet(v) == v) cycle.push_back(v);
if((int)cycle.size() == 2) return 0;
if((int)cycle.size() > 1) {
for(int i = 0; i < (int)cycle.size(); ++i) {
int u = cycle[i];
int v = cycle[(i + 1) % cycle.size()];
g[u][v] = g[v][u] = 1;
}
}
++t;
}
build(g);
return 1;
}
컴파일 시 표준 에러 (stderr) 메시지
supertrees.cpp: In function 'int construct(std::vector<std::vector<int> >)':
supertrees.cpp:82:15: warning: suggest parentheses around '&&' within '||' [-Wparentheses]
82 | if(U == V && p[u][v] != 1 || U != V && p[u][v] != 2) return 0;
| ~~~~~~~^~~~~~~~~~~~~~~
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